The heat of combustion for methanol is 727 kj/mol
<em><u>calculation</u></em>
calculate the moles of methanol (CH3OH)
moles = mass/molar mass
molar mass of methanol = 12 +( 1 x3) +16 + 1= 32 g /mol
moles is therefore= 64.0 g / 32 g/mol = 2 moles
Heat of combustion is therefore = 1454 Kj / 2 moles = 727 Kj/mol
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Answer:
the health codes would not cover the food service complaints
The formula for chromium (III) phosphate trihydrate is CrPO4- 3H20. This compound if in the anhydrous state, exists as a green crystal whereas a hydrated form violet crystal. The formula for cobalt(II) phosphate octahydrate is Co3(PO4)2•8H2O.
Answer:
1.216mol
Explanation:
The molar mass of C₄H₁₀ is (12 x4)+ (1x 10) = 48 + 10 = 58g
1 grams C4H10 is equal to 0.017205129881525 mole.
70.7 grams = 70.7 x 0.017205129881525 = 1.216mol