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andriy [413]
2 years ago
14

A chunk of silver has a heat capacity of 42.8j and a mass of 181g calculate the specific heat of silver.

Chemistry
1 answer:
kifflom [539]2 years ago
7 0
 The  specific  heat  of silver   is calculated as  below

Q(heat)  =  M(mass) xC(specific heat capacity)  

Q= 42.8 j/c

M=181 g
C=?
by  making  C  the subject of the formula

C= Q/M

C= 42.8 j/c/181 g  =0.236j/g/c
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By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm
kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

3 0
1 year ago
What volume in milliliters of 6.0 M NaOH is needed to prepare 175mL of 0.20 M NaOH by dilution?
Ilya [14]

Answer:

V¹N²= V²N²

here V¹= ?

N¹= 6.00

V²= 175ml

M²= 0.2M

So V¹= (V²N²)/N² = (175 x 0.2)/6

V¹ = 5.83 ml

Explanation:

Therefore diluting 5.83 ml of 6.00M NaOH to 175 m l ,we get 0.2M Solution.

4 0
1 year ago
What is the best description of what has happened to flowers when they change color as they mature?
SVEN [57.7K]

Answer:

The answer is (A)

Explanation:

When the weather changes, nature also changes because most plants rely on photosynthesis and if they don't get as much light then they can't support as much as they used causing them to shut down parts of the plant.

6 0
2 years ago
An example of a physical property of an element is the element’s ability to(1) react with an acid(2) react with oxygen(3) form a
ivanzaharov [21]
4 sounds correct......
4 0
2 years ago
You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
12345 [234]

Answer:

M=0.727M

Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

n_{Cl^-}=0.50L*0.250\frac{molFeCl_3}{L}*\frac{3molCl^-}{1molFeCl_3}=0.375molCl^-  \\\\n_{Cl^-}=0.425L*0.350\frac{molBaCl_2}{L}*\frac{2molCl^-}{1molBaCl_2}=0.2975molCl^-

So the total mole of chloride ions:

N_{Cl^-}=0.2975mol+0.375mol=0.6725molCl^-

And the total volume by adding the volume of each solution in L:

V=0.500L+0.425L=0.925L

Finally, the molarity turns out:

M=\frac{0.6725molCl^-}{0.925L}\\ \\M=0.727M

Best regards.

5 0
2 years ago
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