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2 years ago

Which of the following is not the same as 0.032 liters?

1 answer:

3 0

This question needs the answer choices.

I found these choices for you:
0.00032hL
320cL
32mL

Then you need to make the conversion of 0.032 liters to hectoliters, centiliters and milimilters to check which is not equivalent.

1) 0.032 liters to hectoliters:

 0.032 liter * 1 hectoliter / 100 liter = 0.00032 hecoliter

2) 0.032 liter to centiliters:

 0.032 liter * 100 centiliters / 1 liter = 3.2 centiliter

3) 0.032 liter to mililiter:

 0.032 liter * 1000 mililiter / liter = 32 mililiter

Then, the answer is 320 cL: 320 cL is not the same as 0.032 liters

You might be interested in

A 220.0 gram piece of copper is dropped into 500.0 grams of water 24.00 °C. If the final temperature of water is 42.00 °C, what

FrozenT [24]

Answer:

C. 481 °C.

Explanation:

At equilibrium:

The amount of heat absorbed by water = the amount of heat released by copper.

To find the amount of heat, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of energy.

m is the mass of substance.

c is the specific heat capacity.

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T).

∵ Q of copper = Q of water

∴ - (m.c.ΔT) of copper = (m.c.ΔT) of water

m of copper = 220.0 g, c of copper = 0.39 J/g °C, ΔT of copper = final T - initial T = 42.00 °C - initial T.

m of water = 500.0 g, c of water = 4.18 J/g °C, ΔT of water = final T - initial T = 42.00 °C - 24.00 °C = 18.00 °C.

∴ - (220.0 g)( 0.39 J/g °C)(42.00 °C - Ti) = (500.0 g)(4.18 J/g °C)(18.00 °C)

∴ - (85.8)(42.00 °C - Ti) = 37620.

∴ (42.00 °C - Ti) = 37620/(- 85.8) = - 438.5.

∴ Ti = 42.00 °C + 438.5 = 480.5°C ≅ 481°C.

So, the right choice is: C. 481 °C.

4 0

2 years ago

Which of the following statements is true concerning the reaction given below?2H2S(g) + O2(g) → 2S(s) + 2H2O(g)a. The reaction i

pantera1 [17]

Answer:

The rate law may be determined only by experiment.

Explanation:

For a reaction, A + B ---> C, the rate law can only be determined from experimental data. Chemists determine the rate of reaction by carefully observing the changes in the concentration of species as the reaction progresses.

Hence, the rate law is not determined by inspection of the chemical reaction equation, it must be obtained from the experimental data, hence the answer given.

8 0

2 years ago

What is the mass of 0.921 moles of sulfur dioxide gas (SO2)?

Serhud [2]

Answer:

mass = 58.944 g

Explanation:

Given data:

Number of moles of SO₂ = 0.921 mol

Mass of SO₂ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

First of all we will calculate the molar mass.

SO₂ = 32 + 16×2 = 64 g/mol

Now we will put the values in formula.

Number of moles = mass/ molar mass

0.921 mol = mass /64 g/mol

mass = 0.921 mol × 64 g/mol

mass = 58.944 g

8 0

1 year ago

Use average bond energies to calculate ΔHrxn for the following hydrogenation reaction: H2C=CH2(g)+H2(g)→H3C−CH3(g)

marissa [1.9K]

Answer:

The $\Delta H_{rxn}$ of the given reaction is -129.6 kJ

Explanation:

The given chemical reaction is as follows.

$H_{2}C=CH_{2}(g)+H_{2}(g)\rightarrow H_{3}C-CH_{3}(g)$

Enthalpy of each reactant and products are as follows.

$\Delta H_{C=C}\,=615.0\,kJ\,mol^{-1}$

$\Delta H _{H-H}\,=435.1\,kJ\,mol^{-1}$

$\Delta H _{C-C}\,=347.3\,kJ\,mol^{-1}$

$\Delta H _{C-H}\,=416.2\,kJ\,mol^{-1}$

In the given chemical reaction involved two C-H bonds in the reactant side and one C-C bond in the product side therefore, the enthalpy of formation will be the negative.

$\Delta H_{rxn}=-\Delta H_{C-C}-2\Delta H_{C-H}+\Delta H_{C=C}+\Delta H_{H-H}$