Answer:
[C] carbon solid
Explanation:
Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.
H h I ointment o on NB j. Non b kkkk NB nis o ok kno kno
Answer:
A.0.20M
Explanation:
c 1 V 1 = c 2 V 2
Initial Volume, V1 = 200 mL
Final Volume, V2 = 200 + 400 = 600 mL
Initial Concentration, c1 = 0.60 M
Final Concentration, c2= ?
Solving for c2;
c2 = c1v1 / v2
c2 = 0.60 * 200 / 600
c2 = 0.20M
The final temperature of the water is the equilibrium temperature, or the also the final temperature of the iron after a long period of time. Applying the conservation of energy:
m,iron*C,iron*ΔT = - m,water*C,water*ΔT
The density of water is 1000 g/mL.
(25 g)(0.449 J/g·°C)(T - 398 K) = - (25 mL)(1000 g/mL)(4.18 J/g·°C)(T - 298)
Solving for T,
<em>T = 298.01 K</em>
Answer:
Al (s) + AgClO3 (aq) will result in a chemical reaction.
Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)
Cd(s) + CuNO3(aq) will also result in a chemical reaction.
Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu
Explanation:
For chemical reactions, metals lower on the activity series cannot normally displace ions of metals higher than them in the activity series.
Metals at the lower end of the activity series are not easily oxidized.
The activity series is attached to this solution. (Note: Cadmium is not on the attached chart, but Cadmium is between Iron (Fe) & Cobalt (Co) on the activity series)
- Pb is way lower Mg in the activity series, hence, it cannot become oxidized by displacing Mg2+ ion in solution.
- Al is way higher than Ag in the activity series. Hence it will easily be oxidized and displace displace Ag from it's solution easily.
- Cadmium will displace Copper in solution too because Cd is higher than Cu on the activity series.
- Platinum cannot displace Cobalt from solution as Pt is lower than Co on the activity series.