2 years ago

What is the percent composition of a solution in which 480 grams of sodium chloride, NaCl, is dissolved in 4 liters of solution.

Chemistry

1 answer:

ZanzabumX [31]2 years ago

8 0

12% NaCl is the answer I came to... Have a GREAT day!!! :)

You might be interested in

X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc

Cerrena [4.2K]

Explanation:

Given: $\lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}$

Its frequency $\nu$ is defined as

$\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}$

$\:\:\:\:= 3.58×10^{16}\:\text{Hz}$

7 0

1 year ago

The accepted value is 1.43. Which correctly describes this student’s experimental data?

Natalija [7]

Answer:

Neither accurate nor precise

Explanation:

The values were not near or even the same as the accepted value thus making it neither accurate nor precise.

4 0

2 years ago

Read 2 more answers

The three‑dimensional structure of a generic molecule is given. Identify the axial and equatorial atoms in the three‑dimensional

Dima020 [189]

Answer:

Explanation:

CHECK THE ATTACHMENT FOR THE COMPLETE QUESTION AND THE DETAILED EXPLANATION

NOTE:

Equatorial atoms are referred to atoms that are attached to carbons in the cyclohexane ring which is found at the equator of the ring.

Axial atoms are atoms that exist in a bond which is parallel to the axis of the ring in cyclohexane

4 0

2 years ago

In the synthesis of barium carbonate from an alkali metal carbonate (M2CO3 where M is one of the alkali metals) a student genera

Paraphin [41]

Answer:

0.019 moles of M2CO3

Explanation:

M2CO3(aq) + BaCl2 (aq) --> 2MCl (aq) + BaCO3(s)

From the equation above;

1 mol of M2CO3 reacts to produce 1 mol of BaCO3

Mass of BaCO3 formed = 3.7g

Molar mass of BaCO3 = 197.34g/mol

Number of moles = Mass / Molar mass = 3.7 / 197.34 = 0.0187 ≈ 0.019mol

Since 1 mol of M2CO3 reacts with 1 mol of BaCO3,

1 = 1

x = 0.019

x = 0.019 moles of M2CO3

3 0

2 years ago

What is the concentration of a solution made with 0.150 moles of KOH in 400.0 mL of solution?

otez555 [7]

Answer:

$concentration = \frac{0.15}{0.4}=0.375 mol/L$

Explanation:

Concentration: i is defined as the mole per litre.

$concentration = \frac{mole}{volume in L}$

mole=0.15

volume=400 ml=0.4 litre

$concentration = \frac{0.15}{0.4}=0.375 mol/L$

6 0

2 years ago