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2 years ago

What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3

2 answers:

6 0

First we will calculate the number of moles of Iron:
$n = \frac{m}{M}
$ , where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
$n= \frac{84.9}{55.845} = 1,52$ moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So $1,52= \frac{mOxygen}{32}$ where 32 is the Atomical Weight of Oxygen (16 x 2).
=> $mOxygen=32*1,52=48,64$ g

saul85 [17]2 years ago

3 0

Answer:

36.385 grams of oxygen reacts when 84.9 grams of iron.

Explanation:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Moles of iron = $\frac{84.9 g}{56 g/mol}=1.5160 mol$

According to reaction, 4 moles of iron reacts with 3 moles of oxygen gas.

Then 1.5160 moles of iron will react with:

$\frac{3}{4}\times 1.5160 mol=1.1370 mol$ of oxygen gas

Mass of 1.1370 moles of oxygen gas:

$1.1370 mol\times 32 g/mol=36.385 g$

36.385 grams of oxygen reacts when 84.9 grams of iron.

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Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat

Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is $v_{rms}= 207.06 m/s$

Explanation:

From the question we are told that

The temperature is $T = -65 ^oC = -65+273 = 208K$

Root Mean Square velocity is mathematically represented as

$v _{rms} = \sqrt{\frac{3RT}{MW} }$

Where T is the temperature

MW is the molecular weight of gas

R is the gas constant with a value of $R = 8.314 JK^{-1} mol^{-1}$

For CF2Cl2 its molecular weight is 0.121 kg/mol

Substituting values

$v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }$

$v_{rms}= 207.06 m/s$

5 0

2 years ago

Read 2 more answers

What is the chemical formula of a compound that is composed of the ions Camc007-1.jpg and Brmc007-2.jpg?

AlekseyPX

Calcium ions have oxidation state 2+ => Ca (2+).

Bromime ions (bromide) have oxidation state 1- => Br (-).

So, to be neutral the compound has to have two Br (-) ions per each Ca(2+) ion.

That is represented in the chemical formula as Ca Br2, where the number 2 to the right of Br is a subscript meaning that there are two atoms of Br per each atom of Ca (the lack of subscript means 1 atom).

Answer: Ca Br2.

6 0

2 years ago

Read 2 more answers

Each answer below describes the connectivity around a single atom.

MrRissso [65]

Answer:

d. One single bond and two double bonds.

Explanation:

The octate rule is a chemical rule in which the atoms prefer to have eight electrons in the valence shell. Where a single bond provide two electrons and a double bond provide 4 electrons. Thus:

a. Two double bonds . Two double bonds provide 8 electrons. Octate rule is not violated

b. Three single bonds and one pair of electrons . Three single bonds provide 6 electrons and one pair of electrons provide two electrons. Thus, you have eight electrons and octate rule is not violated

c. Two single bonds and one double bond . Two single bonds provide four electrons and one double bond 4. Thus, you have eight electrons and octate rule is not violated.

d. One single bond and two double bonds. One single bond provides two electrons and two double bonds 8. Thus, you have 10 electrons and octate rule is violated.

e. Four single bonds. Four single bonds provide 8 electrons. Octate rule is not violated.

I hope it helps!

4 0

2 years ago

7.744 Liters of nitrogen are contained in a container. Convert this amount to grams.

Xelga [282]

Answer:

9.69g

Explanation:

To obtain the desired result, first let us calculate the number of mole of N2 in 7.744L of the gas.

1mole of a gas occupies 22.4L at stp.

Therefore, Xmol of nitrogen gas(N2) will occupy 7.744L i.e

Xmol of N2 = 7.744/22.4 = 0.346 mole

Now let us convert 0.346 mole of N2 to gram in order to obtain the desired result. This is illustrated below:

Molar Mass of N2 = 2x14 = 28g/mol

Number of mole N2 = 0.346 mole

Mass of N2 =?

Mass = number of mole x molar Mass

Mass of N2 = 0.346 x 28

Mass of N2 = 9.69g

Therefore, 7.744L of N2 contains 9.69g of N2

7 0

2 years ago

0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction

algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce $\frac{2}{1}$ = $\frac{x}{0.50}$

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

$\frac{2}{2}$ = $\frac{x}{0.6}$

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

$\frac{2}{3}$ = $\frac{x}{0.9}$

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0

2 years ago