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SVETLANKA909090 [29]
2 years ago
12

the air we breathe is approximately 21% oxygen.atypical breath has a volume of 450 ml.how many grams of O2 are in a breath of ai

r
Chemistry
1 answer:
nirvana33 [79]2 years ago
6 0
<span>We breathe around an average of 500 ml of air in 1 normal (or relax) breathing. The lungs already have around 3 litres of reserve breathing. Since there is around 21% oxygen in air, we breathe in around 105 ml of Oxygen from the air. That is equal to around 0.14 g of Oxygen.</span>
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Calculate the energy for one mole of photons (an einstein) for light absorbed at 6.90 × 102 nm.
Kay [80]
We know that:
f * λ = c 
<span>and
E = h*f
so,rearranging:
 </span> 
<span>E/h = C/λ 
given:
h = </span><span>6.90 × 10^2 nm

</span><span>substituting the values:

E = </span> C/λ<span> x h  
(c is the speed of light;that is 3x10^8 m/s)

</span>    = 3x10^8 x 6.626x10^-34 / 6.90 x10^7m x 6.022x10^23
Hence,
using calculator:
we get,
 E = 1.69 x 10^5 Joules
5 0
2 years ago
Read 2 more answers
Products or solutions found at home or in store and their characteristics
AleksAgata [21]

Answer:

bruh, just go in your bathroom and look for cleaning products

Explanation:

4 0
1 year ago
A 12.00g sample of MgCl2 was dissolved in water. 0.2500mol of AgNO3 was required to precipitate all the chloride ions from the s
Jlenok [28]

Answer:

Purity=99\%

Explanation:

Hello,

In this case, the undergoing precipitation reaction is:

MgCl_2+2AgNO_3\rightarrow Mg(NO_3)_2+2AgCl

Thus, for the 0.2500 moles of silver nitrate, the following mass of magnesium chloride is consumed (consider their 2:1 molar ratio):

m_{MgCl_2}=0.2500molAgNO_3*\frac{1molMgCl_2}{2molAgNO_3} *\frac{95.2gMgCl_2}{1molMgCl_2} \\\\m_{MgCl_2}=11.90gMgCl_2

Therefore, the purity of the sample is:

Purity=\frac{11.90g}{12.00g}*100\%\\ \\Purity=99\%

Best regards.

7 0
1 year ago
or the reaction: 2X 3Y r 3Z, the combination of 2.00 moles of X with 2.00 moles of Y produces 1.75 moles of Z. What is the perce
Tanzania [10]

Answer:

% yield = 58.33 %

Explanation:

  • 2X + 3Y → 3Z

∴ moles X = 2.00 mol

∴ moles Y = 2.00 mol

∴ moles Z = 1.75 mol = moles produced

  • % Yield = ( moles produced / theoretical moles ) × 100

theoretical moles:

⇒ moles Z = (2.00 mol X)*(3 mol Z/2 mol X) = 3.00 mol Z

⇒ % yield = [(1.75 mol produced)/(3.00 theoretical mol)]×100

⇒ % yield = 58.33 %

4 0
1 year ago
How many moles are there in 45.0 grams of sulfuric acid,<br> H2SO4?
olga2289 [7]

Answer:

the answer is 0.4588162459

Explanation:

1 mole = 0.010195916576195

= 45 ×"

5 0
2 years ago
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