At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2
at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root:
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769
<span>Answer:
Zn(2+) + 2e(-) -------> Zn
1 mole of Zn is deposited by 2F of electricity ...
so 48.9 mole of Zn will be deposited by 48.9 X 2F = 97.8 F of electricity...
as 1F = 96500 C
so 97.8 F = 97.8 X 96500 = 9437700 C of electricity...</span>
Basically team B would win since it is exerting a force of 900N unlike team A ( you can tell by doing 4900N minus 4000N ). It is very unbalanced.
Answer:
3.00 cm
Explanation:
The absorbance can be expressed using <em>Beer-Lambert's law</em>:
A = ε*b*c
Where ε is a constant for each compound, b is the optical path, and c is the molar concentration of the compound.
Now we <u>match the absorbance values for both solutions</u>, because we want the absorbance value to be the same for both solutions:
A = ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M
And <u>solve for b:</u>
ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M
1.00 cm * 7.68x10⁻⁶M = b * 2.56x10⁻⁶ M
b = 3.00 cm
Answer:
<u />
- <u>There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.</u>
<u />
Explanation:
Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.
<u>1. Find the molar mass of SF₆:</u>
Atom atomic mass number of atoms total mass in 1 mole
S 32.065 g/mol 1 32.065 g
F 18.998 g/mol 6 6 × 18.998 = 113.988 g
=====================
molar mass of SF₆ = 146.053 g/mol
<u>2. Find the number of moles in 0.35 g of SF₆:</u>
- number of moles = mass in grams / molar mass
- number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol
<u>3. Find the molar mass of NH₃:</u>
Atom atomic mass number of atoms total mass 1 mole
N 14.007 g/mol 1 14.007 g
H 1.008 g/mol 3 3 × 1.008 g = 113.988 g
=====================
molar mass of NH₃ = 17.031 g/mol
<u />
<u>4. Find the mass in 0.0024 mol of NH₃:</u>
- mass in grams = number of moles × molar mass
- mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams
<u>5. Conclusion: </u>
There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.