Question

Time Remaining: 1:27:31 If 50.0 g of H₂ and 100.0 g of O₂ react, how many moles of H₂O can be produced in the reaction below? 2 H₂(g) + O₂(g) → 2 H₂O(g

Answer 1

Answer:

Explanation:

2 H₂(g) + O₂(g) → 2 H₂O(g

2 moles     1 mole      2 mole

50 g of H₂ = 50 /2 = 25 moles of H₂

100 g of O₂ = 100 / 32 = 3.125 moles of O₂

So oxygen is the limiting reagent .

3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .

Hence moles of H₂O produced = 6.25 moles .