Answer : The value of ΔH for this reaction is, -1516 kJ/mol
Explanation :
First we have to calculate the moles of 
Now we have to calculate the ΔH for this reaction.
As, 2.5 mole of react to gives heat = -3790 kJ
So, 1 mole of react to gives heat = 
= -1516 kJ/mol
Therefore, the value of ΔH for this reaction is, -1516 kJ/mol
Answer:
2.94x10²² atoms of Cu
Explanation:
We must work with NA to solve this, where NA is the number of Avogadro, number of particles of 1 mol of anything.
Molar mass Cu = 63.55 g/mol
Mass / Molar mass = Mol → 3.11 g / 63.55 g/m = 0.0489 moles
1 mol of Cu has 6.02x10²³ atoms of Cu
0.0489 moles of Cu, will have (0.0489 .NA)/ 1 = 2.94x10²² atoms of Cu
Answer:5.1g
Explanation:number of moles of Na2co3 is 0.0485 and it molar mass = 23×2+12+16×3=106
n=m/M
Therefore m= n×M
m= 0.0485×106
=5.141g
Answer : Use of spectrophotometry to study the absorbance changes during the course of reaction which can confirm that tetraamine copper(II) sulfate is formed or not is by comparing the absorbance of the solution with the literature absorbance value of tetraamine copper(II) sulfate. After comparison if both are found to be almost similar then it can be confirmed that tetraamine copper(II) sulfate is the product formed.
The wavelength of![[Cu (NH_{3})_{4}]^{2+}](https://tex.z-dn.net/?f=%20%5BCu%20%28NH_%7B3%7D%29_%7B4%7D%5D%5E%7B2%2B%7D%20)
is less than λ max for 
because it absorbs in the range of shorter wavelength of yellow light. Therefore, the solution appears to be deep blue-violet color.
Hey there:
1 cm³ = 1 mL
D = m / V
7.25 = 12.9 / V
V = 12.9 / 7.25
V = 1.779 cm³
