Answer:
The answer to your question is: 6 moles of HNO₃
Explanation:
Data
Volume = 25 ml
Concentration = 6 M HNO₃
Diluted 100 ml
Formula
Molarity = # moles / volume
# of moles = Volume x Molarity
Process
# of moles = 0.10 x 6
= 6 moles
Answer:
-1273.3
Explanation:
Enthalpy of formation of a compound is the amount of heat absorbed or evolved when one mole of the compound is formed from other compounds.
enthalpy of formation Of CO2 = 2 X -393.5 = -787
enthalpy of formation Of C2H5OH = 2 X -277.7 = -555.4
enthalpy of formation Of C6H12O6 = 69.1 (reverse sign) + (-787 + -555.4) = - 1273.3 Joules
Answer:
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Explanation:
Volume of NaOH = 1.7 ml = 0.0017 L
Molarity of NaOH = 0.0811 M
Moles of NaOH = n
n = 0.0001378 mol

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.
Then 0.0001378 mol of NaOH will neutralize:
of sulfuric acid.
Concentration of sulfuric acid in the acid rain sample: x

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
2 atoms in a molecule of RSq, TSq contains 3 different types of atoms (Sq, R, and T.)
I don’t think I could answer this sorry.........