Answer:
The true statements are given below.
Explanation:
1 D glucose is a reducing sugar
2 The oxidation of reducing sugar forms a carboxylic acid sugar.
D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.
The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).
I know this isn't the answer but here's an English translation
<span>The saturated vapor pressure of pure water at 20 ° C is 18 mmHg. If at the same temperature as much as 120 grams of x-substance dissolved in 990 grams of water, the vapor pressure of the solution becomes 17.37 mmHg, calculate the relative molecular mass of the substance x?</span>
When KOH and Cu(NO3)2 are mixed it yields copper(II) hydroxide and potassium nitrate. The balanced reaction is:
Cu(No3)2(aq) + 2 KOH(aq)<span> = Cu(OH)2(s) + 2 KNo3(aq)
</span>
As we can see from the equation a solid is formed therefore a
precipitate is formed which is the copper (II) hydroxide which has a blue to
purple appearance. This can be observed since copper
(II) hydroxide has a low
solubility in aqueous solution.
AgI has a higher melting point than vanillin because it is an ionic compound. The bonds are held more tightly together than in vanillin because it is a covalent compound. Ionic bonds have a higher melting point because the electrons are being transferred from one atom to the other.
Answer : The correct option is A.
Explanation :
Enzyme-catalyzed reaction :
Enzyme act as a biological catalyst and the role of catalyst is to increase the rate of chemical reaction by lowering the activation energy.
Most of the chemical reactions are slow in the absence of enzyme but in the presence of enzyme, the reaction become faster. That means the Enzyme accelerate the rate of reaction.
Therefore, the correct answer is the reaction is faster than the same reaction in the absence of the enzyme.
