Let's Assign Symbols to molecules like,
C₂O₄ = X
and
H₂O = Y
Then,
K [ Co (X)₂ (Y)₂ ]
As, Potassium (K) has a O.N = +1
To neutralize, the coordination sphere must have -1 oxidation number.
So,
[ Co (X)₂ (Y)₂ ] = -1
As,
O.N of X = -2
Then
O.N of (X)₂ = -4
Also,
O.N of H₂O is zero as it is neutral, So,
[Co - 4 + 0 ] = -1
Or,
Co = -1 + 4
Co = +3
Result:
Oxidation Number of Coordination Sphere is -1 and Oxidation Number of Cu is +3.
Answer:
25.7 kJ/mol
Explanation:
There are two heats involved.
heat of solution of NH₄NO₃ + heat from water = 0
q₁ + q₂ = 0
n = moles of NH₄NO₃ = 8.00 g NH₄NO₃ × 1 mol NH₄NO₃/80.0 g NH₄NO₃
∴ n = 0.100 mol NH₄NO₃
q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln
m = mass of solution = 1000.0 g + 8.00 g = 1008.0 g
q₂ = mcΔT = 58.0 g × 4.184 J°C⁻¹ g⁻¹ × ((20.39-21)°C) = -2570.19 J
q₁ + q₂ = 0.100 mol ×ΔHsoln – 2570.19 J = 0
ΔHsoln = +2570.19 J /0.100 mol = +25702 J/mol = +25.7 kJ/mol
Answer:
8
Explanation:
To solve this question, we just need to put the new number into the equation. If [A] remain constant then that mean [A2]= [A1]. If B doubled, then that mean [B2]= 2[B2]. To find what factor does the rate of reaction increases, we need to divide the first reaction rate with the second. The calculation will be:
rate2/rate1= k[A2][B2]³ / k[A1][B1]³
rate2/rate1= [A1][2B1]³ / [A1][B1]³
rate2/rate1= A1*8B1³ / A1*B1³
rate2/rate1= 8/1= 8
The rate of reaction will be 8 times faster.