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kodGreya [7K]
1 year ago
10

. Hemoglobin (Hb) and oxygen gas form a complex (HbO2) that carries oxygen throughout the human body. Unfortunately, carbon mono

xide also binds to hemoglobin so that an equilibrium is established. Carbon monoxide poisoning occurs when the concentration of HbO2 in the blood is reduced. HbO2 CO HbCO O2 The first aid for a person suffering from carbon monoxide poisoning is to (1) remove them to an area of fresh air, and (2) administer oxygen. Using the principles of equilibrium, explain how each of these helps to restore the HbO2 concentration.
Chemistry
1 answer:
sp2606 [1]1 year ago
5 0

Answer:

1. Removing them to an area of fresh air. This helps to prevents further poisoning by the carbon monoxide and increase the amount of oxygen entering into the body. This will help to reduce the concentration of carbon monoxide binding oxygen

2. Administering pure oxygen goes a long way to enhance ventilation and increase the oxygen saturation to 100%. This will help to overcome the effect of the carbon monoxide and promote more hemoglobin binding

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A gem has a mass of 4.50 g. When the gem is placed in a graduated cylinder 12.00 mL of water, the water level rises to 13.45 mL.
Mandarinka [93]
<span>Displaced volume :

</span>Final volume - <span>Initial volume

</span>13.45 mL - 12.00 mL => 1.45 mL

Mass =  4.50 g

Therefore:

density = mass / volume

D = 4.50 / 1.45

<span>D = 3.103 g/mL </span>
6 0
1 year ago
In a 1 M solution of NH3(aq), identify the relative molar amounts of these species. Arrange them from most to least.
Lera25 [3.4K]

Answer:

928933

Explanation:

carbon hydrated

8 0
2 years ago
What molecule is the ultimate source of hydrogen ions that are secreted into the gastric juice?
sladkih [1.3K]

Answer: carbonic acid

Explanation:

8 0
2 years ago
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. NH4l, CoBr3, Na2
seraphim [82]
Answer:

NaI > Na2SO4 > Co Br3

meaning that NaI has the highest freezing point, and Co Br3 has the lowest freezing point.

Explanation:

The freezing point depression is a colligative property.

That means that it depends on the number of solute particles dissolved.

The formula to calculate the freezing point depression of a solution of a non volatile solute is:

ΔTf = i * Kf * m

Where kf is a constant, m is the molality and i is the van't Hoff factor.

Molality, which is number of moles per kg of solvent, counts for the number of moles dissolved and the van't Hoff factor multipllies according for molecules that dissociate.

The higher the number of molecules that dissociate, the higher the van't Hoff, the greater the freezing point depression and the lower the freezing point.

As the question states that you assume equal concentrations (molality) and complete dissociation you just must find the number of ions generated by each solute, in this way:

NH4 I → NH4(+) + I(-) => 2 ions

Co Br3 → Co(+) + 3 Br(-) => 4 ions

Na2SO4 → 2Na(+) + SO4(2-) => 3 ions.

So, Co Br3 is the solute that generate more particles and that solution will exhibit the lowest freezing point among the options given, Na2SO4 is next and the NaI is the third. Ordering the freezing point from higher to lower the rank is NaI > Na2SO4 > CoBr3, which is the answer given.
4 0
1 year ago
Given the following equation and heat of reaction: 2 moles of A combine with 2 moles of B to produce 6 moles of C and 26 kJ What
Hoochie [10]

Answer: The change in enthalpy will be -13.

Explanation:-

Endothermic reactions are those in which heat is absorbed by the system and exothermic reactions are those in which heat is released by the system.

\Delta H for Endothermic reaction is positive and  \Delta H for Exothermic reaction is negative.

2A+2B\rightarrow 6C+26kJ  

2A+2B\rightarrow 6C       \DeltaH=-26kJ

When 1 mole of A combining with 1 mole of B to produce 3 moles of C

Thus as the stoichiometry has got half of the original , enthalpy of the reaction will also get half.

Thus for reaction :

A+B\rightarrow 3C+\frac{26}{2}kJ  

A+B\rightarrow 3C       \DeltaH=-13kJ

Thus the change in enthalpy will be -13.

8 0
1 year ago
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