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krek1111 [17]
2 years ago
9

The pressure of a 609.64 gram sample of F2 in a 88.84 L container is measured to be 2770.96 torr. What is the temperature of thi

s gas in Kelvin?
Chemistry
1 answer:
Oxana [17]2 years ago
4 0

Answer : The temperature of the gas is, 245.9 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT

where,

P = pressure of gas = 2770.96 torr = 3.646 atm

Conversion used : (1 atm = 760 torr)

V = volume of gas = 88.84 L

T = temperature of gas = ?

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas = 609.64 g

M = molar mass of F_2 gas = 38 g/mole

Now put all the given values in the ideal gas equation, we get:

(3.646atm)\times (88.84L)=\frac{609.64g}{38g/mole}\times (0.0821L.atm/mole.K)\times (T)

T=245.9K

Therefore, the temperature of the gas is, 245.9 K

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Answer:

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Explanation:

Energy of the photon can be calculated by

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where,

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h = Planck's constant = 6.63\times 10^{-34}Js

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we have , \lambda =510 nm=510\times 10^{-9}m

Now put all the given values in the above formula, we get the energy of the photons.

E=\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{510\times 10^{-9}m}

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2 years ago
What fraction of the carbon dioxide exhaled by animals is generated by the reactions of the citric acid cycle
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Answer:

1/3

Explanation:

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1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.

Also,  

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Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)

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2 years ago
Looking at the same nonmetal group on the periodic table, how does the reactivity of an element in period 2 compare to the react
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Answer : Option B) The period 2 element would be more reactive because the attractive force of protons is stronger when electrons are attracted to a closer electron shell.

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1 year ago
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Answer: The initial volume of the system is 60.29 L.

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According to the first law of thermodynamics,

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As it is given that heat is being added to the system so, \Delta H will be positive. And, work done on the system is negative and work done by the system is positive.

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or,        W = P (V_{final} - V_{initial})

So,       \Delta U = Q - P (V_{final} - V_{initial})

            -107.4 J = 52.7 J - 0.693 \times 101.325 (63.2 - V)

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Thus, we can conclude that the initial volume of the system is 60.29 L.

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