The pressure of a 609.64 gram sample of F2 in a 88.84 L container is measured to be 2770.96 torr. What is the temperature of thi
1 answer:
Answer : The temperature of the gas is, 245.9 K
Explanation :
To calculate the temperature of gas we are using ideal gas equation:
where,
P = pressure of gas = 2770.96 torr = 3.646 atm
Conversion used : (1 atm = 760 torr)
V = volume of gas = 88.84 L
T = temperature of gas = ?
R = gas constant = 0.0821 L.atm/mole.K
w = mass of gas = 609.64 g
M = molar mass of gas = 38 g/mole
Now put all the given values in the ideal gas equation, we get:
Therefore, the temperature of the gas is, 245.9 K
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Answer:
[H₃O⁺] = 4.3 × 10⁻¹² mol·L⁻¹; [OH⁻] = 2.4 × 10⁻³ mol·L⁻¹;
pH = 11.4; pOH = 2.6
Explanation:
The chemical equation is
For simplicity, let's re-write this as
1. Calculate [OH]⁻
(a) Set up an ICE table.
B + H₂O ⇌ BH⁺ + OH⁻
0.310 0 0
-x +x +x
0.310-x x x
Check for negligibility:
(b) Solve for [OH⁻]
2. Calculate the pOH
3. Calculate the pH
4 Calculate [H₃O⁺]
3.98 x 10⁻¹⁹ Joule
<h3>Further explanation</h3><u>Given:</u>
The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.
<u>Question:</u>
The energy of a photon of green light (in joules).
<u>The Process:</u>
The energy of a photon is given by
- E = energy in joules
- h = Planck's constant 6.63 x 10⁻³⁴ Js
- f = frequency of light in Hz (sometimes the symbol f is written as v)
Let us find out the energy of the green light emitted per photon.
Thus, we get a result of
- - - - - - - - - -
Notes
- When an electron moves between energy levels it must emit or absorb energy.
- The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
- A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
- The energy of the orange light emitted per photon brainly.com/question/2485282#
- Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
- Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146
Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules
<u>Answer:</u> The number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively
<u>Explanation:</u>
In a chemical equation, the chemical species are termed as reactants or products.
Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.
Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.
For the given chemical equation:
On the reactant side:
Number of carbon atoms = (6 × 2) = 12
Number of hydrogen atoms = (14 × 2) = 28
Number of oxygen atoms = (2 × 19) = 38
Hence, the number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively