Name the region of the atom where protons and neutrons are located. This region is indicated by label B. Name the region of the
2 answers:
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<h3>Answer:</h3>
1.1 mol Ne
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[Given] 6.5 × 10²³ atoms Ne
[Solve] moles Ne
<u>Step 2: Identify Conversion</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.07938 mol Ne ≈ 1.1 mol Ne
<u>Answer:</u>
<u>For 1:</u> The correct answer is False.
<u>For 2:</u> The correct answer is True.
<u>For 3:</u> The correct answer is True.
<u>For 4:</u> The correct answer is False.
<u>For 5:</u> The correct answer is True.
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions. If no net ionic equation is formed, it is said that no reaction has occurred.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form. Solids, liquids and gases do not exist as ions.
- <u>For 1:</u> Lead(II) nitrate and sodium chloride
The chemical equation for the reaction of lead (II) nitrate and sodium chloride is given as:
Ionic form of the above equation follows:
As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the correct answer is False.
- <u>For 2:</u> Sodium bromide and hydrochloric acid
The chemical equation for the reaction of sodium bromide and hydrochloric acid is given as:
Ionic form of the above equation follows:
There are no spectator ions in the equation. So, the above reaction is the net ionic equation.
Hence, the correct answer is True.
- <u>For 3:</u> Nickel (II) chloride and lead(II) nitrate
The chemical equation for the reaction of lead (II) nitrate and nickel (II) chloride is given as:
Ionic form of the above equation follows:
As, nickel and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the correct answer is True.
- <u>For 4:</u> Magnesium chloride and sodium hydroxide
The chemical equation for the reaction of magnesium chloride and sodium hydroxide is given as:
Ionic form of the above equation follows:
As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the correct answer is False.
- <u>For 5:</u> Ammonium sulfate and barium nitrate
The chemical equation for the reaction of ammonium sulfate and barium nitrate is given as:
Ionic form of the above equation follows:
As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the correct answer is True.