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Shalnov [3]
2 years ago
8

Suppose a container holds 1000 hydrogen molecules (H2) and 1000 oxygen molecules (O2) that react to form water. How many water m

olecules will be in the container? Will anything else be in the container? If so, what?
Chemistry
1 answer:
mezya [45]2 years ago
8 0
500 water molecules and the remaining 500 O2 molecules. Remember the ratio of H to O in H2O.
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Which feature of the evaporating dish makes it effective in the evaporation process
tigry1 [53]
The precise fit on the ring stand. The ability to hold more substance than a test tube. A shallow bottom to increase the surface area of a liquid, leaving the solid behind.
4 0
2 years ago
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An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?
Alinara [238K]
If the atom is neutral then, the total number of electrons is the same as the number of protons. We calculate for the total number of electrons given the compressed electron configuration,
   number of electrons of Xenon (Xe) = 54
The total number of electrons after Xenon,
   = 2 + 14 + 7 = 23

Adding up all the number of electrons, we have,
   total number of electrons = 54 + 23 = 77

The identity of this element is Iridium (Ir). This element belongs to the class of Group 9. This is the transition metal. 
8 0
2 years ago
A solution of sodium acetate (ch3coona) in water is weakly basic. <br> a. True <br> b. False
guajiro [1.7K]
Hello!

The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:

Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:

CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)

Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.

Have a nice day!
7 0
2 years ago
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
2 years ago
A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to the stoi- chiometric point.
Dmitrij [34]

Answer:

Molar concentration of the weak acid solution is 0.0932

Explanation:

Using the formula: \frac{C_aV_a}{C_bV+b}  = \frac{n_a}{n_b}

Where Ca = molarity of acid

Cb = molarity of base = 0.0981 M

Va = volume of acid = 25.0 mL

Vb = volume of base = 23.74 mL

na = mole of acid

nb = mole of base

Since the acid is monopromatic, 1 mole of the acid will require 1 mole of NaOH. Hence, na = nb = 1

Therefore, C_a = \frac{C_bV_b}{V_a}

Ca = 0.0981 x 23.74/25.0

                 = 0.093155 M

To 4 significant figure = 0.0932 M

3 0
2 years ago
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