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Archy [21]
2 years ago
15

Arrange the sublevels in ascending order by the number of electrons they can contain. p sublevel s sublevel d sublevel f subleve

Chemistry
2 answers:
kirza4 [7]2 years ago
4 0

s-sublevel has 1 orbital - it can have maximum 2 electrons.


p-sublevel has 3 orbitals - it can have maximum 6 electrons


d-sublevel has 5 orbitals - it can have maximum 10 electrons


f-sublevel has 7 orbitals - it can have maximum 14 electrons.



inn [45]2 years ago
3 0

Electronic configuration of the atom describes  the arrangemnet of electrons in different shells and subshells ( sublevels).

Now , there are 4 types of sublevels: s, p , d and f . These sublevels have orbital which are spaces with high probability of having an electron and each orbital can have maximum 2 electrons.

Therefore,

s-sublevel has 1 orbital - it can have maximum 2 electrons.

p-sublevel has 3 orbitals - it can have maximum 6 electrons

d-sublevel has 5 orbitals - it can have maximum 10 electrons

f-sublevel has 7 orbitals - it can have maximum 14 electrons.

Hence, the acsending order of sublevels in terms of maximum number of electrons is:

<h2>s < p < d < f</h2>
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Bonds between two atoms that are equally electronegative are _____. bonds between two atoms that are equally electronegative are
Anna [14]
Bonds of two atoms of equal electronegativity are nonpolar covalent bonds.

Your second sentence is identical to the first sentence; I'll bet the second sentence is "Bonds between two atoms that are unequally electronegative are polar covalent bonds."
4 0
2 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
2 years ago
Which compound has the lowest vapor pressure at 50°C?
Mnenie [13.5K]

Answer : Option A) Ethanoic Acid


Explanation : Ethanoic acid has the lowest vapor pressure i.e 0.08 atm at the temperature of 50°C compared to the other given options.


The vapour pressure of propanone at 50°C is 0.84 atm

Ethanol has vapour pressure as 0.30 atm at 50°C

water has vapour pressure of 0.12 atm at 50°C.


7 0
2 years ago
Read 2 more answers
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0
2 years ago
Use the virtual lab to prepare 150.0 ml of an iodine solution with a concentration of 0.06 g/ ml from the bottle of 0.12g/ml iod
son4ous [18]

Answer:

Explanation:

In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g

Let volume of given concentration of .12 g / ml required be V

In volume V , gram of iodine = V x .12 g

According to question

V x .12 = 9 g

V = 9 / .12 = 75 ml

So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .

8 0
2 years ago
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