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masya89 [10]
2 years ago
6

Some hydrogen gas is enclosed within a chamber being held at 200∘C∘C with a volume of 0.0250 m3m3. The chamber is fitted with a

movable piston. Initially, the pressure in the gas is 1.50×106Pa1.50×106Pa (14.8 atmatm). The piston is slowly extracted until the pressure in the gas falls to 0.950×106Pa0.950×106Pa. What is the final volume V2V2V_2 of the container? Assume that no gas escapes and that the temperature remains at 200∘C∘C.
Chemistry
1 answer:
Semenov [28]2 years ago
3 0

Answer:

The final volume is 39.5 L = 0.0395 m³

Explanation:

Step 1: Data given

Initial temperature = 200 °C = 473 K

Volume = 0.0250 m³ = 25 L

Pressure = 1.50 *10^6 Pa

The pressure reduce to 0.950 *10^6 Pa

The temperature stays constant at 200 °C

Step 2: Calculate the volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.50 * 10^6 Pa

⇒with V1 = the initial volume = 25 L

⇒with P2 = the final pressure = 0.950 * 10^6 Pa

⇒with V2 = the final volume = TO BE DETERMINED

1.50 *10^6 Pa * 25 L = 0.950 *10^6 Pa * V2

V2 = (1.50*10^6 Pa * 25 L) / 0.950 *10^6 Pa)

V2 = 39.5 L = 0.0395 m³

The final volume is 39.5 L = 0.0395 m³

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The density of liquid Z is 0.9237 g/mL. A student masses a cup
Ulleksa [173]

Answer:

37.65mL

Explanation:

Given parameters:

density of liquid  Z = 0.9237g/mL

Mass of liquidZ + mass of cup = 50.7g

Mass of cup= 15.92g

Volume of liquid Z in cup=?

Solution:

 Density is the mass per unit volume of a substance. It is mathematically expressed as shown below:

    Density = \frac{mass}{volume}

To find the volume of liquid Z, we know the density of the liquid but we dont know the mass yet.

Mass of liquidZ = 50.7g - mass of cup = 50.7g - 15.92g = 34.98g

Therefore:

 Volume of liquidZ = \frac{mass of liquidZ}{density of liquidZ}

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3 0
1 year ago
What is the mass in grams of 7.5 x 10^15 atoms of nickel?
satela [25.4K]
Atomic mass Ni = 58.69 a.m.u

58.69 g ----------------- 6.02x10²³ atoms
?? g --------------------- 7.5x10¹⁵ atoms

58.69x (7.5x10¹⁵) / 6.02x10²³

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6 0
2 years ago
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Please Help Me!!
Cerrena [4.2K]

Answer:

1. Galvanic oxidation. Example is the corrosion of aluminium wires when in contact with copper wires under wet conditions.

2. Rainwater or Damp/moist air

3. Chromium-plated steel screws or stainless steel screws or galvanized steel screws

Explanation:

1. Galvanic oxidation or corrosion occurs when two different metals with different electrode potentials are brought into contact with each other by means of an electrolyte (usually a aqueous solution), such that a redox reaction occurs leading to one metal with the more negative electrode potential (the anode) becoming oxidized, while the other less negative potential (the cathode) is reduced.

In order for galvanic corrosion to occur, three elements are required.

i. Two metals with different corrosion potentials (anode and cathode)

ii. Direct metal-to-metal electrical contact

iii. A conductive electrolyte solution (e.g. water) must connect the two metals on a regular basis.

For example oxidation (corrosion) of aluminium wires when in contact with copper wire under wet conditions.

2. The most likely electrolyte will be rainwater containing dissoved solutes (if the panel is in an exposed part of the house) or damp/moist air.

3. From the table, the most likely screw will be chromium-plated steel screws or stainless steel (made of iron and nickel) screws or galvanized steel (zinc-plated) screws.

All these possible screw components have a more negative electrode potential than copper. Thus they will serve as the anode in a galvanic oxidation with copper.

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Answer:

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Explanation:

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It is a molecules of a single element made up of 8 sulfur atoms.

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It is a symbol of an element named cesium.

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It is a symbol of an element named oxygen.

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It is a molecule of a single element made up of 2 oxygen atoms.

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It is a molecule of a single element made up of 3 oxygen atoms.

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It is compound composed of carbon and hydrogen element.

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It is a symbol of an element named sulfur.

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