answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Norma-Jean [14]
2 years ago
5

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31 kilograms. How would you enter this number

into the answer box?Enter your answer in kilograms usingthree significant figures. Note that the units are provided for youto the right of the answer box.m_e = __.
Chemistry
1 answer:
mote1985 [20]2 years ago
5 0

Answer:

The answer is the same as 9.11x10-31kg which is the mass of an electron,

Explanation:

The mass of an electron expressed in standard form is 9.11x10-31, which is the same thing as 0.000000000000000000000000000000911, while the former looks compact and easier to understand, the latter is clumsy,

The concept of three significant figures mean, three non-zero figures, in other words, provide your answer in an approximate form using three figures apart from zero, so you would try to express your answer in such a way that the first digit in your answer is not zero, in this case, its a "nine" - "9", and the other two significant figures are "1" and "1".

You might be interested in
How many molecules are in 70.7 grams of C4H10?
OlgaM077 [116]

Answer:

1.216mol

Explanation:

The molar mass of C₄H₁₀ is (12 x4)+ (1x 10) = 48 + 10 = 58g

1 grams C4H10 is equal to 0.017205129881525 mole.

70.7 grams = 70.7 x 0.017205129881525  = 1.216mol

6 0
2 years ago
Read 2 more answers
How many grams of nano3 would you add to 500g of h2o in order to prepare a solution that is 0.500 molal in nano3?
VARVARA [1.3K]
When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.

0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3

Since the molar mass of NaNO3 is 85 g/mol, the mass is

0.25 mol * 85 g/mol = 21.25 grams NaNO3 needed
4 0
2 years ago
Suppose a soap manufacturer starts with a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic
DIA [1.3K]

Answer:

Sodium arachidate; Sodium palmitate and Sodium palmitate

Explanation:

Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.

Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.

For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.

Arachidic acid will react with NaOH to yield sodium arachidate.

The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.

8 0
1 year ago
How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
Colt1911 [192]
How many carbon atoms are there in a 1.3-carat diamond? Answer: 1.3 x 10^22 C atoms...
If a 1 carat = 0.20 g ... then 0.3 carat = 0.20 / 0.3 = 0.06 g
Thus, 1.3 carat = 0.26g
Find the moles first:
Moles= Grams / Mm of C
0.26 / 12.011 = 0.0216 mols of C
Atoms = Moles * Avogadro's number (6.022*10^23)
0.0216 * 6.022*10^23 = 1.3*10^22 C atoms

Hope this helps! :)
8 0
2 years ago
Read 2 more answers
Think of an everyday situation in which two objects interact and exert a force on each other. Explain how the interaction can ca
blondinia [14]

Answer:

It's explained below.

Explanation:

An everyday situation is when we raise an object.

Now, when we raise an object, energy is transferred to the Earth object system and thus the gravitational field energy of the system will increase.

Now, this energy is usually released when the object falls. The mechanism of this release is known as gravitational force.

In the same manner, two magnetic and electrically charged objects that are interacting at a distance will exert forces on each other and this can lead to transfer of energy between the interacting objects.

6 0
2 years ago
Other questions:
  • How do moss leaves and fish differ? How are they the same?
    11·1 answer
  • A gas is contained in a thick-walled balloon. When the pressure changes from 319 mm Hg to 215 mm Hg, th volume changes from 0.55
    9·2 answers
  • You have a mixture that contains 0.380 moles of Ne(g), 0.250 moles of He(g), and 0.500 moles CH4(g) at 400 K and 7.25 atm. What
    11·1 answer
  • How many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromiu
    11·1 answer
  • Name the complex ion [cu(cn)6]4−. the oxidation number of copper is +2.enter the name.
    12·1 answer
  • What is the freezing point of a 1.40 m aqueous solution of a nonvolatile un-ionized solute? (the freezing point depression const
    14·1 answer
  • Aluminum–lithium (Al–Li) alloys have been developed by the aircraft industry to reduce the weight and improve the performance of
    8·1 answer
  • The infrared spectrum above represents the absorption of certain wavelengths of radiation by molecules of CO2. Which of the foll
    9·1 answer
  • Consider the following reaction (X = Cl or Br) which statement s is are correct?
    10·1 answer
  • A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!