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uysha [10]
2 years ago
7

Make a drawing of the particles in an NaCl solution to show why this solution conducts electricity. Make a drawing of the partic

les in an NaCl crystal to show why pure salt does not conduct.

Chemistry
1 answer:
cluponka [151]2 years ago
5 0

Answer:

  • See the image attached. It is taken from an online chemistry textbook.

  • See the explanation below.

Explanation:

<em>Sodium chloride</em> consits of sodium cations (positive ions), Na⁺, and chloride anions (negative ions), CL⁻.

<u>Pure sodium chloride</u> is packed in crystals: sodium ions and chloride ions are packed together and the ions are in fixed positions. There are not free electrons that can move. Thus, sodium chloride doesn't conduct electricity, because there are no electrons or ions which are free to move.

In aqueous solution, sodium chloride units dissociates into their ions:

         NaCl\rightarrow Na^++Cl^-

Those ions are freely to move in the solution, and such they are charge carriers, which conduct the electricity.

As explained above, in solid sodium chloride, the ions cannot move and there is not flow of current.

That is why solid pure salt of NaCl does not conduct electricity and the solutions of NaCl do conduct electricity.

The image attached show both diagrams. In the diagram A, the ions are packed together, showing that they cannot move. In the diagram B, the ions are dissolved in water, showing that they can move and carry the charge, allowing the flow of current.

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Answer:

a, b

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Electrolytes dissociate to make ions, because of it  they conduct electricity.

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Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
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CN^- is a strong field ligand

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The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).

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2 years ago
How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaC
nexus9112 [7]

Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with \frac{6.2}{2} = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

6 0
2 years ago
Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
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First you should know that there is seven oxygen atoms in one Mn2O7
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Then you multiply this no. with Avagadro no....
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Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen... 
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