Make a drawing of the particles in an NaCl solution to show why this solution conducts electricity. Make a drawing of the partic
les in an NaCl crystal to show why pure salt does not conduct.
1 answer:
Answer:
- See the image attached. It is taken from an online chemistry textbook.
- See the explanation below.
Explanation:
<em>Sodium chloride</em> consits of sodium cations (positive ions), Na⁺, and chloride anions (negative ions), CL⁻.
<u>Pure sodium chloride</u> is packed in crystals: sodium ions and chloride ions are packed together and the ions are in fixed positions. There are not free electrons that can move. Thus, sodium chloride doesn't conduct electricity, because there are no electrons or ions which are free to move.
In aqueous solution, sodium chloride units dissociates into their ions:
Those ions are freely to move in the solution, and such they are charge carriers, which conduct the electricity.
As explained above, in solid sodium chloride, the ions cannot move and there is not flow of current.
That is why solid pure salt of NaCl does not conduct electricity and the solutions of NaCl do conduct electricity.
The image attached show both diagrams. In the diagram A, the ions are packed together, showing that they cannot move. In the diagram B, the ions are dissolved in water, showing that they can move and carry the charge, allowing the flow of current.
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Answer : The vapor pressure (in atm) of a solution is, 0.679 atm
Explanation : Given,
Mass of = 1.00 kg = 1000 g
Moles of = 3.68 mole
Molar mass of = 18 g/mole
Vapor pressure of water = 0.692 atm
First we have to calculate the moles of .
Now we have to calculate the mole fraction of
Now we have to partial pressure of solution.
According to the Raoult's law,
where,
= vapor pressure of solution
= vapor pressure of water = 0.692 atm
= mole fraction of water = 0.938
Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm
Answer: The concentration of excess in solution is 0.017 M.
Explanation:
1.
moles of
1 mole of give = 1 mole of
Thus 0.019 moles of give = 0.019 mole of
2. moles of
According to stoichiometry:
1 mole of gives = 2 moles of
Thus 0.012 moles of give =
moles of
As 1 mole of neutralize 1 mole of
0.019 mole of will neutralize 0.019 mole of
Thus (0.024-0.019)= 0.005 moles of will be left.
Thus molarity of in solution is 0.017 M.