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Virty [35]
1 year ago
8

Brooke decides to model a lunar eclipse. She attaches a large poster of the Sun to her wall to represent the Sun. She then decid

es that her head will represent Earth, and the direction she is facing will indicate the direction an observer on Earth is facing. She will then hold a small ball in her hand to represent the Moon. In order to model a person watching a lunar eclipse, Brooke faces the "Sun," stretches out her hand, and faces the "Moon" in front of her. What aspect of Brooke's model should be corrected?
A. Brooke should turn so that the Sun is on her right, and hold the Moon to her left.
B. Brooke should turn so that her back is to the Sun, and hold the Moon behind her.
C. Brooke should turn so that the Sun is on her left, and hold the Moon in front of her.
D. Brooke should turn so that her back is to the Sun, and hold the Moon in front of her.
PLEASE HELP ITS A TEST :(((
Chemistry
1 answer:
koban [17]1 year ago
7 0

Answer:

its D

Explanation:

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En una determinación cuantitativa se utilizan 17.1 mL de Na2S2O3 0.1N para que reaccione todo el yodo que se encuentra en una mu
lozanna [386]

Answer:

La cantidad de yodo en la muestra es 0.217 g

Explanation:

Los parámetros dados son;

Normalidad de la solución de Na₂S₂O₃ = 0.1 N

Volumen de la solución de Na₂S₂O₃ = 17.1 mL

Masa de muestra = 0.376 g

La ecuación de reacción química se da de la siguiente manera;

I₂ + 2Na₂S₂O₃ → 2 · NaI + Na₂S₄O₆

Por lo tanto, el número de moles de sodio por 1 mol de Na₂S₂O₃ en la reacción = 1 mol

Por lo tanto, la normalidad por mol = 1 M × 1 átomo de Na = 1 N

Por lo tanto, 0.1 N = 0.1 M

El número de moles de Na₂S₂O₃ en 17,1 ml de solución 0,1 M de Na₂S₂O₃ se da de la siguiente manera;

Número de moles de Na₂S₂O₃ = 17.1 / 1000 × 0.1 = 0.00171 moles

Lo que da;

Un mol de yodo, I₂, reacciona con dos moles de Na₂S₂O₃

Por lo tanto;

0,000855 moles de yodo, I₂, reaccionan con 0,00171 moles de Na₂S₂O₃

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La masa de yodo en la muestra = 253.8089 × 0.000855 = 0.217 g.

5 0
2 years ago
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The relationship between the ρ (h) = ρ(c) X \frac{T_{h}}{T_{c}}

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2 years ago
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