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Fynjy0 [20]
2 years ago
12

Draw structures for all constitutional isomers with the molecular formula c2h5cl

Chemistry
1 answer:
Rudiy272 years ago
4 0
Constitutional isomers<span> are compounds that have the same molecular formula but different connectivity.

To determine whether two molecules are </span>constitutional isomers<span>, just count the number of each atom in both molecules and see how the atoms are arranged.
If both molecules have the same count for </span>all<span> of the different atoms, </span>and<span> the atoms are arranged in different ways (i.e. their </span>connectivity<span> is different), then they will be constitutional isomers.

In this case C2H5Cl will not have any constitutional isomer. Because you can attach the Cl on first carbon or second carbon, both structure will be same. There will only exist one structure. Figure is attached</span>

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Rubbing alcohol contains 615g of isopropanol (C3H7OH) per liter (aqueous solution). Calculate the molality of this solution. Giv
faltersainse [42]

Answer:

Solution of isopropanol is 10.25 molal

Explanation:

615 g of isopropanol (C3H7OH) per liter

We gave the information that 615 g of solute (isopropanol) are contained in 1L of water. We need to find out the mass of solvent, so we use density.

Density of water 1g/mL → Density = Mass of water / 1000 mL of water

Notice we converted the L to mL

Mass of water = 1000 g (which is the same to say 1kg)

Molality are the moles of solute in 1kg of solvent, so let's convert the moles of isopropanol  → 615 g . 1mol / 60g = 10.25 moles

Molality (mol/kg) = 10.25 moles / 1kg = 10.25 m

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2 years ago
Players 1, 2, 3 are playing a tournament. Two of these three players are randomly chosen to play a game in round one, with the w
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The answer & explanation for this question is given in the attachment below.

6 0
2 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5C w/ 1,150 g of water at 25.0C . if the final temperature of the system is
vichka [17]
Remember: heat lost = heat gained 

When calculating heat loss or gain, remember 

mass*(spec heat cap)*(change in T) 

The unknown loses heat- we don't know the spec heat cap, so we'll call it x.

The water gains. I've omitted the units, but always use when solving problems on your own. 

75*x*(96.5-37.1) = 1150*4.184*(37.1-25) 
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Now it's all set up- use algebra to get x, the spec heat cap of the unk in J/g*degC

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Explain how manipulation of light waves can cause reflection, refraction, diffusion, and absorption; and describe how different
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Answer:is A

Explanation:

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2 years ago
Oxalic acid is a diprotic acid. calculate the percent of oxalic acid (h2c2o4) in a solid given that a 0.7984-g sample of that so
vlada-n [284]
This method of quantitative determination of percent purity is titrimetric reactions. These reactions most commonly involve neutralization reactions between an acid and a base. Then, we look at the neutralization reaction:

H₂C₂O₄ + 2 NaOH ⇒ Na₂C₂O₄ + 2 H₂O

So, we do the stoichiometric calculations. The important data we should know is the molar mass of oxalic acid which is equal to 90 g/mol.

(0.2283 mol/L NaOH * 0.3798 L * 1 mol H₂C₂O₄/ 2mol NaOH * 90 g/mol H₂C₂O₄) ÷ 0.7984 g *100%
= 488%

This is impossible. The purity can't be more than 100%. Looking at our calculations and the balance reaction, all steps were done correctly. So, I think there is some typographical error in the given. The mass of the sample should be 7.984 g. Then, the answer would be 48.87% purity.
5 0
2 years ago
Read 2 more answers
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