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Fynjy0 [20]
1 year ago
12

Draw structures for all constitutional isomers with the molecular formula c2h5cl

Chemistry
1 answer:
Rudiy271 year ago
4 0
Constitutional isomers<span> are compounds that have the same molecular formula but different connectivity.

To determine whether two molecules are </span>constitutional isomers<span>, just count the number of each atom in both molecules and see how the atoms are arranged.
If both molecules have the same count for </span>all<span> of the different atoms, </span>and<span> the atoms are arranged in different ways (i.e. their </span>connectivity<span> is different), then they will be constitutional isomers.

In this case C2H5Cl will not have any constitutional isomer. Because you can attach the Cl on first carbon or second carbon, both structure will be same. There will only exist one structure. Figure is attached</span>

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Unit Conversion Help Thank you
AlekseyPX

Answer : 1721.72 g/qt are in 18.2 g/cL

Explanation :

As we are given: 18.2 g/cL

Now we have to convert 18.2 g/cL to g/qt.

Conversions used are:

(1) 1 L = 100 cL

(2) 1 L = 1000 mL

(3) 1 qt = 946 qt

The conversion expression will be:

\frac{18.2g}{1cL}\times \frac{100cL}{1L}\times \frac{1L}{1000mL}\times \frac{946mL}{1qt}

=1721.72\text{ g/qt}

Therefore, 1721.72 g/qt are in 18.2 g/cL

5 0
2 years ago
Calculate the Lattice Energy of KCl(s) given the following data using the Born-Haber cycle: ΔHsublimation K = 79.2 kJ/mol IE1 K
DanielleElmas [232]

Answer:

Explanation:

  The following equation relates to Born-Haber cycle

\triangle H_f = S + \frac{1}{2} B + IE_M - EA_X+ U_L

Where

\triangle H_f is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

IE_M is ionisation enthalpy of metal

EA_X is electron affinity of non metal atom

U_L is lattice energy

Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

U_L = - 707 KJ / mol

3 0
1 year ago
Which quantity can vary among atoms of the same element?
Wewaii [24]
There is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number
7 0
2 years ago
In KCI how are the valence electrons distributed
-BARSIC- [3]

Answer:

Explanation:

In KCL, the elements to combine to form KCl are K and Cl.

Potassium (K) is an element of group 1 and they're known to have 1 valence electron in its outer most orbital. This electron is donated and used for bonding. It is every element desirability to attain octet or duet electronic configuration I.e by having 2 electrons or 8 electrons in its outer orbital. Potassium has a lower electro negativity and higher ionization energy, hence it is easier to donate electron than to recieve it. Meanwhile, Chlorine (Cl) is an element of group 17 which are characterized for having 7 electrons in its outermost orbital requiring just one electron to form an octet configuration, chlorine has a higher electro negativity and lower ionization energy hence it is easier to accept electron than to donate it.

The nature of bond formed from K and Cl to give KCl is called electrovalent bonds.

Equation of reaction

K + Cl → KCl

3 0
1 year ago
2. The diagram below shows steps in the exothermic chemical reaction of bromomethane with
vovangra [49]

Answer:

Here's what I get  

Explanation:

1. Balanced equation

HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻

(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)

2. Mechanism

HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻

        A                           C                         B

The hydroxide ion attacks the back side of the carbon atom in the bromomethane (A).

At the same time as the Q-H bond starts to form, the C-Br bond starts to break.

At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.

As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).

3. Energy diagram

See the diagram below.

 

8 0
2 years ago
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