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2 years ago

How many particles would be found in a 12.7g sample of ammonium carbonate

Chemistry

1 answer:

Semenov [28]2 years ago

4 0

Answer: The sample of ammonium carbonate contains

0.560 mol NH

Explanation:The chemical formula for ammonium carbonate is

(

)

. The formula indicates that in one mole of ammonium carbonate, there are two moles of ammonium ions,

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One container of turns costs 4 dollars. Each container has eighty 1g tablets. Assume each turns is 40% caco₃. Using only turns,

stealth61 [152]

Answer: The cost is coming out to be $ 1.25

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of HCl solution = 0.4 M

Volume of solution = 0.5 L

Putting values in equation 1, we get:

$0.4M=\frac{\text{Moles of HCl}}{0.5L}\\\\\text{Moles of HCl}=(0.4mol/L\times 0.5L}=0.2mol$

The chemical equation for the reaction of HCl and calcium carbonate follows:

$CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2$

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, 0.2 moles of HCl will react with = $\frac{1}{2}\times 0.2=0.1mol$ of calcium carbonate

To calculate the mass of calcium carbonate for given moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of calcium carbonate = 100 g/mol

Moles of calcium carbonate = 0.1 moles

Putting values in equation 1, we get:

$0.1mol=\frac{\text{Mass of calcium carbonate}}{100g/mol}\\\\\text{Mass of calcium carbonate}=(0.1mol\times 100g/mol)=10g$

Calculating the mass of calcium carbonate in 1 container:

We are given:

One container contains eighty 1 g of tablets, this means that in total 80 g of tablets are there.

Every container has 40 % calcium carbonate.

Mass of calcium carbonate in 1 container = 40 % of 80 g = $\frac{40}{100}\times 80=32g$

Calculating the containers for amount of calcium carbonate that neutralized HCl by using unitary method:

32 grams of calcium carbonate is present in 1 container

So, 10 g of calcium carbonate will be present in = $\frac{1}{32}\times 10=0.3125$ container

Calculating the cost of turns:

1 container of turns costs $4

So, 0.3125 containers of turns will cost = $\frac{\$ 4}{1}\times 0.3125=\$ 1.25$

Hence, the cost is coming out to be $ 1.25

4 0

2 years ago

Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3, at 500 K. PCl3(g) + Cl2(g) PCl5(g) If the VOLUM

7nadin3 [17]

Answer:

The value of Kc C. remains the same.

The value of Qc C. is less than Kc.

The reaction must: A. run in the forward direction to reestablish equilibrium

The number of moles of Cl2 will B. decrease.

Explanation:

Le Chatelier's Principle states that if a system in equilibrium undergoes a change in conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.

A decrease in volume causes the system to evolve in the direction in which there is less volume, that is, where the number of gaseous moles is less.

But temperature is the only variable that, in addition to influencing equilibrium, modifies the value of the constant Kc. So if the volume of the equilibrium system is suddenly decreased at constant temperature: The value of Kc remains the same.

As mentioned, if the volume of an equilibrium gas system decreases, the system moves to where there are fewer moles. In this case, being:

PCl₃(g) + Cl₂(g) ⇔ PCl₅(g)

The equilibrium in this case then shifts to the right because there is 1 mole in the term on the right, compared to the two moles on the left. So, The reaction must: A. run in the forward direction to reestablish equilibrium.

By decreasing the volume, and so that Kc remains constant, being:

$Kc=\frac{[PCl_{5} ]}{[PCl_{3}]*[Cl_{2} ]}=\frac{\frac{nPCl_{5} }{Volume} }{\frac{nPCl_{3}}{Volume}*\frac{nCl_{2} }{Volume} } =\frac{nPCl_{5}}{nPCl_{3}*nCl_{2}} *Volume$

where nPCl₅, nPCl₃ and nCl₂ are the moles in equilibrium of PCl₅, PCl₃ and Cl₂

so, the number of moles of Cl₂ should decrease.The number of moles of Cl2 will B. decrease.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system will evolve to the right, the direct reaction prevailing, to increase the concentration of products. So in this case, if the reaction moves to the right, the value of Qc C. is less than Kc.

3 0

2 years ago

The temperature at the boiling point remained constant despite the continued addition of heat by the bunsen burner. What was the

Paul [167]

Concept:

Latent Heat of Vaporization: It is defined as the amount of heat required to change the state of mater without changing of its temperature.

From the given question, the temperature at the boiling point remained constant despite the continued addition of heat by the Bunsen burner. Actually, this amount of heat is used by water to break the intermolecular bonds between the water molecules in the form of latent heat that converts the liquid state of water into vapor state of water.

Hence, the correct option will be d.The energy was used to break the intermolecular bonds between the water molecules.

3 0

2 years ago

The highest elevation Mt. Zembat in Alaska 40 years ago was measured at 7600 feet. Today the highest elevation is 7598 feet. Wha

a_sh-v [17]

It's simple:
rate of change = change in height / time period

= (7600 - 7598) / 40 = 2 / 40 = 0.05 feet / yr

3 0

2 years ago

A) To generate the spectrum above a source capable of producing electromagnetic radiation with an energy of 7 * 10 ^ 4 * k * J p

marin [14]

Answer:

Gamma

Explanation:

I'm not sure how to do it without calculations but:

E=hv

7*10^7 J/mol=6.626*10^34 Js * v

v=1*10^41

Gamma rays.

More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

3 0

2 years ago

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