Question

In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen) by diving to a depth of 124 m. Assume that he takes a breath that fills his lungs to 3.6 L at the surface of the water (1.0 atm). Calculate the volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m. Enter the answer in units of liters.

Answer 1

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}$

${V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L$

${V_2}=0.27\ L$

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.