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Alik [6]
2 years ago
7

How many liters of a 0.352 M solution of Ca(SO4) would contain 62.1 g of Ca(SO4)?​

Chemistry
1 answer:
konstantin123 [22]2 years ago
4 0

Answer:

1.3 L.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of CaSO₄)/(Volume of the solution (L))</em>

<em></em>

M = 0.352 M.

no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,

Volume of the solution = ??? L.

∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))

<em>∴ (Volume of the solution (L) </em>= (0.456 mol)/(0.352 M) = <em>1.296 L ≅ 1.3 L.</em>

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Answer:

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Explanation:

From the given data, we have two categories of variables (unknowns):

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The longer route would be to solve for these variables first, by determining the number of moles of the Caffeine sample (0.134 moles of C8H10N4O2) from the mass of carbon (12.89 g = 1.07 moles in 6.47 10^{22} atoms) provided. And then solve for the number of atoms of H. <u><em>[N.B: 1 mole of ANY substance = 6.022 × </em></u>10^{22}<u><em> atoms ]</em></u>

Alternatively and quicker, we can use the mole ratios of the Carbon:Hydrogen atoms in the compound.

8 : 10 ≡ 4 : 5

If   4 moles -- 6.47 10^{22} atoms

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⇒ No. of atoms of Hydrogen = \frac{5*6.47*10^{22}}{4}

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2 years ago
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