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Alik [6]
2 years ago
7

How many liters of a 0.352 M solution of Ca(SO4) would contain 62.1 g of Ca(SO4)?​

Chemistry
1 answer:
konstantin123 [22]2 years ago
4 0

Answer:

1.3 L.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of CaSO₄)/(Volume of the solution (L))</em>

<em></em>

M = 0.352 M.

no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,

Volume of the solution = ??? L.

∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))

<em>∴ (Volume of the solution (L) </em>= (0.456 mol)/(0.352 M) = <em>1.296 L ≅ 1.3 L.</em>

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