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2 years ago

Determine the chemical formula for the compound, potassiumtrisethylenediamine chromate(III).

Chemistry

1 answer:

Korolek [52]2 years ago

8 0

Answer: The correct answer is (A).

Explanation:

Potassium-trisethylene-diamine chromate(III)

Potassium is coming first in name which means that potassium is present as cation.

In the complex, 3 molecules of 'ethylene-diamine' is present as an dianion and forms a complex with Chromium (III) metal, making the overall charge on the coordination sphere as (-3).

So, to make a neutral complex, 3 potassium ions are required.

Hence, the structure of the complex is $K_3[Cr(NH_2CH_2CH_2NH_2)_3]$

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How many molecules are there in 345 grams of carbon dioxide?

Mekhanik [1.2K]

You take the grams of CO₂ times Avogadro's number divided by the molar mass.

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2 years ago

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What volume is equivalent to 0.0015 m3?

vaieri [72.5K]

Answer : Option 'D' is correct.

$0.0015m^{3}$ = $1.5\times 10^{6}mm^{3}$

Explanation 1) : 1 m = 100 cm

$1 m^{3}= 1000000 cm^{3}$ or $1 m^{3}= 10^{6} cm^{3}$

$(0.0015m^{3})\times \frac{(1000000cm^{3})}{(1m^{3})}$

$(0.0015)\times \frac{(1000000cm^{3})}{(1)}$ = $1500cm^{3}$

$0.0015m^{3}$ = $1500cm^{3}$ = $1.5\times 10^{3}cm^{3}$

Explanation 2) : 1 m = 1000 mm

$1m^{3}= 1000000000mm^{3} = 10^{9}mm^{3}$

$(0.0015m^{3})\times \frac{(10^{9}mm^{3})}{(1m^{3})}$

$(0.0015)\times \frac{(10^{9}mm^{3})}{(1)}$ = $1500000 mm^{3}$

$0.0015m^{3}$ = $1500000 mm^{3}$ = $1.5\times 10^{6}mm^{3}$

Option 'D' is right.

3 0

2 years ago

Which atomic model states that it is impossible to know the exact location of electrons around the nucleus?

dedylja [7]

Answer:

the Bohr model, an electron's position is known precisely because it orbits the nucleus in a fixed path. In the electron cloud model, the electron's position cannot be known precisely. Only its probable location can be known.

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2 years ago

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This stadium can hold 100,000, or 1 x 105, people. The number of atoms in a grain of iron is about 1 x 1018. Would you need 1 x

nata0808 [166]

<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

We are given that;

1 stadium holds = 1 × 10^5 people

Number of iron atoms is 1 × 10^18 atoms

Assuming the stadium would carry an equivalent number of atoms as people.

Then, 1 stadium will carry 1 × 10^5 atoms

Therefore,

To calculate the number of stadiums that can hold 1 × 10^18 atoms we divide the total number of atoms by the number of atoms per stadium.

Number of stadiums = Total number of atoms ÷ Number of atoms per stadium

= 1 × 10^18 atoms ÷ 1 × 10^5 atoms/stadium

= 1 × 10^13 Stadiums

Thus, 1 × 10^18 atoms would occupy 1 × 10^13 stadiums

7 0

2 years ago

Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,

zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

$2 reactant moles*\frac{-184.6kJ}{mol}$

ΔU=-369.2 kJ/mol.

4 0

2 years ago