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Orlov [11]
2 years ago
5

Draw the structure of the amine and carboxylic acid reactants required to form the following amide in an amidation reaction.Draw

the starting amine. Be sure to draw nonbonding electron pairs.
Draw the starting carboxylic acid. Be sure to draw nonbonding electron pairs.

Chemistry
1 answer:
lys-0071 [83]2 years ago
3 0

Answer:

Explanation:

Amidation is a reaction with the formation of an amide. It involves a process where series of reaction between amine and carboxylic acid takes place.

The main objective of this question is to draw with the aid of a diagram.

the structure of the amine and carboxylic acid reactants required to form the following amide in an amidation reaction.

But before that,

we are to draw the starting amine and to be sure to include the nonbonding electron pairs.

Also, to draw  starting carboxylic acid and to be sure to include the nonbonding electron pairs.

The whole series of the diagrammatic expression for the amine formation can be found in the diagram attached below.

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A hydrogen atom is removed from the first carbon atom of a butane molecule and is replaced by a hydroxyl group. draw the new mol
Leno4ka [110]
The new molecule that is formed is an alcohol and is known as butanol. It has a chemical formula CH3CH2CH2CH2OH or C4H9<span>OH</span>. A molecule that has a hydroxyl functional group is an alcohol. It has isomers namely tert-butanol, 2-butanol and isobutanol.
7 0
1 year ago
(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0
2 years ago
7. A gas-filled weather balloon with a volume of 65.0 L is released at sea-level conditions of
Galina-37 [17]

The balloon will reach its maximum volume and it will burst.

Given:

  • A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
  • When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
  • The maximum volume of the weather balloon is 835 L.

To find:

Whether the weather balloon will reach its maximum volume or not.

Solution:

The pressure of the gas in the weather balloon at sea level = P_1=745 torr

1 atm = 760 torr\\P_1=745 torr=\frac{745}{760} torr = 0.980 atm

The volume of the weather balloon at sea level = V_1=65.0L

The temperature of the gas in the weather balloon at sea level:

T_1=25^oC=25+273.15 K=298.15 K

The balloon rises to an altitude.

The pressure of the gas in the weather balloon at the given altitude:

P_2=0.066atm

The volume of the weather balloon at the given altitude = V_2=?

The temperature of the gas in the weather balloon at the given altitude:

T_1=25^oC=25+273.15 K=298.15 K

Using the Combined gas law:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{0.980 atm\times 65.0L}{298.15 K}=\frac{0.066atm\times V_2}{298.15K}\\V_2=\frac{0.980 atm\times 65.0L\times 298.15K}{0.066atm\times 298.15 K}\\=965L

The maximum volume of the weather balloon= V = 835 L

V < V_2

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.

Learn more about the combined gas law:

brainly.com/question/13154969?referrer=searchResults

brainly.com/question/936103?referrer=searchResults

4 0
1 year ago
a solution of household vinegar is to be analyzed. A pipet is used to measure out 10 ml of the vinegar which is placed in a 250m
DerKrebs [107]

Answer:

0.0344 M

Explanation:

  • HC₂H₃O₂ (aq) + OH⁻ (aq) --> C₂H₃O₂⁻ (aq) + H₂O (l)

Because one mol of vinegar (acetic acid) reacts with one mol of NaOH, we can use the formula

  • C₁V₁=C₂V₂

Where C₁ and V₁ refer to the concentration and volume of vinegar, and C₂ and V₂ to those of NaOH. We're given V₁, C₂ and V₂; so we <em>solve for C₁</em>:

  • C₁ = C₂V₂ / V₁
  • C₁ = 0.0500 M * 16.7 mL / 25.0 mL
  • C₁ = 0.0344 M
6 0
2 years ago
For the reaction 3h2(g) + n2(g) 2nh3(g), kc = 9.0 at 350°c. calculate g° at 350°c.
miss Akunina [59]
When ΔG° is the change in Gibbs free energy

So according to ΔG° formula:

ΔG° =  - R*T*(㏑K)

here when K = [NH3]^2/[N2][H2]^3 = Kc 

and Kc = 9 

and when T is the temperature in Kelvin = 350 + 273 = 623 K

and R is the universal gas constant = 8.314 1/mol.K

So by substitution in ΔG° formula:

∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)

           = - 4536 
4 0
2 years ago
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