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2 years ago

How many capsules containing 75mg of Tamiflu could be produced from 155g of star anise.?

1 answer:

7 0

From the question you will find that:
one capsule of tamiflu is obtained from 2.6 g of star anise.
1 capsule = 2.6 g tamiflu
? capsules = 155 g tamiflu
by cross multiplication = $\frac{(1 x 155)}{2.6}$ = 59 capsules

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Give an example of role of luck in bottenheims research

Veronika [31]

"You may find what you seek, or you might not" Is an excellent quote that might help.

3 0

2 years ago

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How many electrons are involved in one equivalent of oxidation-reduction?

kotegsom [21]

Answer:

1 electron is involved.

Explanation:

Hello,

In redox reactions, when therer's the necessity to know the involved equivalents, they equal the number of transferred electrons, in this case, since one equivalent is stated, one electron is transferred (involved).

Best regards.

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2 years ago

The nitrogen content of organic compounds can be determined by the Dumas method. The compound in question is first reacted by pa

MAVERICK [17]

Answer:

Mass percent of nitrogen in the compound is 13,3%

Explanation:

Dumas method is an analytical method to determine nitrogen content in samples, thus:

CₐHₓNₙ + (2a+x/2) CuO → aCO₂ + ˣ/₂ H₂O + ⁿ/₂ N₂ + (2a+x/2) Cu

As the CO₂ is removed with KOH, in the mixture you have H₂O and N₂

At 25°C. the vapor pressure of water is 23,8 torr, that means that the pressure due to N₂ is:

726torr - 23,8torr = 702,2 torr.

Using gas law:

n = PV/RT

Where:

P is pressure (702,2torr≡ 0,924 atm)

V is volume (0,0318L)

R is gas constant (0,082atmL/molK)

And T is temperature (25°C≡298,15K)

Replacing, number of moles of N₂, n, are:

n = 1,20x10⁻³moles of N₂. In grams:

1,20x10⁻³moles of N₂× $\frac{28g}{1mol}$ = 0,0336 g of N₂.

Thus, mass percent of nitrogen in the compound is:

$\frac{0,0336g N}{0,253gSample}$ ×100= 13,3%

I hope it helps!

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2 years ago

Calculate the change in internal energy of the following system: a 100.0-g bar of gold is heated from 25 ∘C to 50 ∘C during whic

NikAS [45]

The Law states that the change in internal energy (U) of the system is equal to the sum of the heat supplied to the system (q) and the work done ON the system (W)
ΔU = q + W 

For the first question, 0.653kJ of heat energy is removed from the system (balloon) while 386J of work is done ON the balloon, thus 
ΔU = -653J + 386J 
=-267J 
Thus internal energy decrease by 267J 

For the second question, 322J of heat energy is added to the system (gold bar) while no work is done on the gold bar, this is an isochoric/isovolumetric process, thus 
ΔU = 322J + 0 
=322J 
Thus internal energy increase by 322J

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2 years ago

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Standard Hydrogen Electrode consists of platinum wire fused in a glass tube and a platinum plate coated with finely divided plat

iris [78.8K]

Answer:

To increase surface area of the platinum electrode which results in superior quality and action of the electrodes as opposed to normal platinum electrodes.

Explanation:

Platinization of Platinum is the process of covering platinum electrode with a layer of platinum black. Platinum black is a finally divided form of platinum, optimized for catalysing the addition of hydrogen to unsaturated organic compound. This increases the surface area of the platinum electrodes and therefore exhibits action superior to that of normal electrodes.

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2 years ago