Answer:
Explanation:
The lewis structure (indicating all the atoms and patterns provided as hint in the question) of glycine can be seen in the attachment below. While the chemical structure of glycine can be seen below
H
|
H₂N - C - C =O
| \
H OH
The structure (of glycine) above provides a "fair idea" of how the lewis structure will be.
Answer and Explanation:
The equation that depicts oxidation of neutral atom A is shown below:

This is because one species is losing electrons due to oxidation. The species possesses positively charged after losing electrons, the magnitude of which is proportional to the number of electrons lost.
The net charge will be equivalent on both sides of the equation, too.
Therefore all other options are not correct
The equation that depicts the decline of neutral atom X is

It is how a cell gains electrons by reduction. The species obtains a negative charge upon possessing electrons, whose magnitude is equivalent to the amount of electrons gained.
The net charge will be equivalent on both sides of the equation, too.
Therefore all other options are not correct
Answer:

Explanation:
Hello,
In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

Thus, we solve for the final pressure P2 to obtain it as shown below:

Hence, we notice that the temperature doubles as well as the pressure.
Best regards.
<u>Answer:</u> The value of
for the reaction at 690 K is 0.05
<u>Explanation:</u>
We are given:
Initial pressure of
= 1.0 atm
Total pressure at equilibrium = 1.2 atm
The chemical equation for the decomposition of phosgene follows:

Initial: 1 - -
At eqllm: 1-x x x
We are given:
Total pressure at equilibrium = [(1 - x) + x+ x]
So, the equation becomes:
![[(1 - x) + x+ x]=1.2\\\\x=0.2atm](https://tex.z-dn.net/?f=%5B%281%20-%20x%29%20%2B%20x%2B%20x%5D%3D1.2%5C%5C%5C%5Cx%3D0.2atm)
The expression for
for above equation follows:


Putting values in above equation, we get:

Hence, the value of
for the reaction at 690 K is 0.05
In order to see which species has the strongest dispersion forces, you need to calculate their molar mass, because the higher the molar mass, the stronger the dispersion forces.
Since E. C8H18 has the highest molar mass, its dispersion forces are also the strongest ones.