Answer:
The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of
as indicated on the spectrum. The reaction between the
and the
are both clear liquids that form the orange liquid product
which creates the absorbance spectrum. Because the color of the solution is orange, it reflects this and similar colors while absorbing blueish hues. We can find the absorption of only the
by pre-rinsing the cuvette with each solution we intend to measure before placing it in the spectrometer. Also, wipe each cuvette with a kimwipe to remove all fingerprints that could effect the data collection.
Explanation:
The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of
as indicated on the spectrum.
Mixture is a combination of two or more substances. The components of the mixture are not chemically reacted and can be separated using physical means.
compound is a combination of two or more substances that are chemically reacted or bound together. The components of the compound cannot be separated except by chemical reactions.
Answer:
<span>(4) consist of two or more substances</span>
Answer is: the highest concentration has ⁺H₃NCH(CH₃)CO₂⁻.
pKa(carboxylic group) = -log(4,5·10⁻³) = 2,35.
pKb(amino group) = -log(7,4·10⁻⁵) = 4,13.
pKa + pKb = 14.
pKa(amino group) = 14 - 4,13 = 9,87.
At pH = 7 carboxylic group lost proton(H⁺) and became COO⁻, amine is protoneted (NH₃⁺) in this pH value.
Answer
% of C in C2H6= (2×12)/30×100=80%
% of H in C2H6= (3×2)/30×100=20%
Explanation:
2C+3H2-C2H6
nC=12, nH=1, nC2H6=30
2moles of C-1mole of C2H6
3moles of H-1 mole of C2H6
% of C in C2H6= (2×12)/30×100=80%
% of H in C2H6= (3×2)/30×100=20%