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Vlad1618 [11]
2 years ago
11

The equilibrium reaction below has the Kc = 4.00 at 25°C. If the temperature of the system at equilibrium is increased to 100°C,

how and for what reason will the equilibrium shift. Also show and explain how and why the Kc value will change.
Chemistry
1 answer:
professor190 [17]2 years ago
6 0

Answer:

Following are the answer to this question:

Explanation:

In the given question information is missing, that is equation which can be defined as follows:

CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)   \ \ \bigtraingleup H^0=+206.2KJ

  • Growing temperatures may change its connection to just the way which consumes thermal energy in accordance with Le chatelier concepts Potential connection is endothermic. Answer: shifts to the right  
  • Kc are described as a related to the concentration by the intensity of both the reaction for each phrase which reaches a power equal towards its stoichiometric equation coefficient  Kc = \frac{product}{reactant}   It increases [product] but reduces [reactant] Therefore, Kc increases
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5.65

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Answer:

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Explanation:

The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of FeNCS^{2+} as indicated on the spectrum.

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One similarity between all mixtures and compounds is that both(1) are heterogeneous(2) are homogeneous(3) combine in a definite
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Answer:
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5 0
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Read 2 more answers
Alanine, h2nch(ch3)co2h, has ka = 4.5  10–3 and kb = 7.4  10–5 . which species has the highest concentration at a ph of 7.00 i
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Answer is: the highest concentration has ⁺H₃NCH(CH₃)CO₂⁻.
pKa(carboxylic group) = -log(4,5·10⁻³) = 2,35.
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pKa + pKb = 14.
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3 0
2 years ago
What is the percentage composition of carbon and hydrogen in ethane(c2h6,molecular mass 30.0)<br>​
My name is Ann [436]

Answer

% of C in C2H6= (2×12)/30×100=80%

% of H in C2H6= (3×2)/30×100=20%

Explanation:

2C+3H2-C2H6

nC=12, nH=1, nC2H6=30

2moles of C-1mole of C2H6

3moles of H-1 mole of C2H6

% of C in C2H6= (2×12)/30×100=80%

% of H in C2H6= (3×2)/30×100=20%

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