<span>We can use
the heat equation,
Q = mcΔT </span>
<span>Where Q is
the amount of energy transferred (J), m is the mass of the substance
(kg), c is
the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is
the temperature difference (°C).</span>
Let's assume that the finale temperature is T.
Q = 1200 J
<span>
m = 36 g
c = 4.186 J/g °C</span>
ΔT = (T -
22)
By applying
the formula,
1200 J = 36 g
x 4.186 J/g °C x (T - 22)
(T - 22) = 1200 J / (36 g x 4.186 J/g °C)
(T - 22) = 7.96 °C
T = (7.96 + 22) °C = 29.96 °C
T = 30 °C
Hence,
the final temperature is 30 °C.
Answer:
Total volume after adding crystal = 26.7 mL
Explanation:
Given data:
Density of crystal = 2.65 g/mL
Mass of sample = 4.46 g
Volume of water = 25.0 mL
Volume after adding crystal = ?
Solution:
First of all we will calculate the volume of crystal.
d = m/v
2.65 g/mL = 4.46 g/ v
v = 4.46 g/2.65 g/mL
v = 1.7 mL
Total volume after adding crystal = Volume of water + Volume of metal
Total volume after adding crystal = 25.0 mL + 1.7 mL
Total volume after adding crystal = 26.7 mL
<h2>
Hello!</h2>
The answer is:
The percent yield of the reaction is 32.45%
<h2>
Why?</h2>
To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.
We are given that:
Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.
So, calculating we have:
Hence, we have that the percent yield of the reaction is 32.45%.
Have a nice day!
Answer:It is not an element because elements are the purest form of a substance; hence, they are no longer broken down by heating
Explanation:
Answer:
CaF2 > Ag2CO3 > Ag3(PO4)2 > Ba3(PO4)2
Explanation:
Ksp which is solubility product konstant shows equilibrium between a solids and its respective ions in a solution. And the lower it is the less soluble the ion compound will be. And for CaF2 we have the highest konstant and for Ba3(PO4)2 we have it the lowest.
