The answer:
<span>The equation of its dissolution in water is: AgNO3 → Ag + (aq) + NO3- (aq)
and </span>AgNO3 → Ag + (aq) + NO3- (aq)
1 mol 1mol 1mol
? -------- 0.854mo
so for finding the value, it is sufficients to complute 1 x 0.854 mol =0.854 mol
so, 0.854 mol is required for the reaction to form 0.854 mol of Ag
<u>Answer:</u> The element represented by M is Strontium.
<u>Explanation:</u>
Let us consider the molar mass of metal be 'x'.
The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol
It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:
The metal atom having molar mass as 87.62/mol is Strontium.
Hence, the element represented by M is Strontium.
Answer:
En toda la población del mundo hay <u>0.0797 moles de células</u>
Explanation:
1.0 mol of cells = 6.022 * 10∧23 cells
X mol of cells = 6.0 * 10∧12 cells
- X is cleared to find out how many moles of cells are in a human body:
- X = 6.0 * 10∧12 cells / 6.022 * 10∧23 cells
- X = 9,963 * 10∧-12 moles of cells per person
In the world there are 8 * 10∧9 people, how many moles in total will there be?
8 * 10∧9 people * 9,963 * 10∧-12 moles of cells per person =
<u>0.0797 moles of molecules in the entire population of the earth.</u>
Glucose is chemical energy for the body, as gasoline (petrol) is chemical energy for the car. Thus, gasoline.
Answer:
A.) 34.866 x 10¯23 g/atom
B.) 2.64 x 10^22 atoms in 1 cm3
C.) 1 atoms per unit cell
Explanation:
A) Calculate the average mass of one atom of polonium:
210g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 34.866 x 10¯23 g/atom
B) Determine atoms in 1 cm3:
9.19g / 34.866x 10¯23 g/atom = 2.64 x 10^22 atoms in 1 cm3
Determine volume of the unit cell:
(3.37 x 10¯8 cm)3 = 3.827 x 10¯23 cm3
Determine number of unit cells in 1 cm3:
1 cm3 / 3.827 x 10¯23 cm3 = 2.61 x 1022 unit cells
C) Determine atoms per unit cell:
2.64 x 1022 atoms / 2.61 x 1022 unit cells = 1 atoms per unit cell
