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1 year ago

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A graduated cylinder initially has 32.5 mL of water in it. After a 75.0 g piece of lead (Pb) is added to the graduated cylinder,

the water level rises to the 39.1 mL mark. What is the the volume of the piece of lead.

1 answer:

Mice21 [21]1 year ago

6 0

Answer:

39.1-32.5 and you will find your answer it always like that, you subtract your starting point from your ending point

Explanation:

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What crossed-aldol product results when butanal is heated in the presence of excess benzaldehyde and sodium hydroxide? draw the

alexdok [17]

Answer:
2-(hydroxy(phenyl)methyl)butanal is formed as cross aldol product.

Explanation:
The mild acidic proton present at alpha position in 1-Butanal is abstracted by strong base NaOH. The enolate formed is the conjugate base of 1-Butanal and cacts as a nucleophile. The enolate is then added across carbonyl group of Benzaldeyde and yield 2-(hydroxy(phenyl)methyl)butanal. The reaction is as follow,

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2 years ago

Two glasses labeled A and B contain equal amounts of water at different temperatures. Kim put an antacid tablet into each of the

skelet666 [1.2K]

Answer:

Option D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Explanation:

Solubilities of solutes are enhanced when the temperature is increased.

From the experiment conducted,

It is evident that glass B temperature is higher than glass A temperature, because the solute dissolves faster in glass B than in glass A . This implies that glass A is cooler than glass B, hence the particles in A will move slower than that in B.

6 0

2 years ago

Read 2 more answers

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}$

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}$

Molarity of HCl left un-neutralized : $\frac{0.00575 moles}{0.350L}=0.0164 M$

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0

2 years ago

If a 300.0 ml sample of a gas is heated at constant pressure from 25.0ºc to 55.0ºc, its new volume is _____ ml?

jekas [21]

The new volume is 330.2 ml

<u><em>calculation</em></u>

The new volume is calculated using the Charles law formula

that is V1/T1= V2/T2

where T1= 25.0 c into kelvin = 25 +273 = 298 K

V1= 300.0 ml

T2 = 55.0 c into kelvin = 273 +55 =328 K

V2 = ? ml

make V2 the subject of the formula by multiplying both side by T2

V2= V1T2/ T1

V2 =[ (300.0 ml x 328 k) / 298 k} = 330.2 ml

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2 years ago

When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala

Orlov [11]

Answer:

q = -176kJ

Explanation:

HCl and NH3 reacts as following to NH4Cl

HCl(g) + NH3(g)=========>NH4Cl(s) : ΔH = -176 KJ

Clearly,

ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .

therefore, the value of heat evolved as q = -176kJ

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1 year ago