Since both samples are pure CH4 (methane), the proportion of C to H that evolves from the decomposition should be equal. In equation form:
35.0 g C / 2.04 g H = 23.0 g C / x g H
Solving for x gives a value of x = 1.3406 g H
So 1.3406 grams of hydrogen will be produced from sample b.
What you need to do is find 1/8 of 50
you can just divide 50 by 8 to get 6.25
so now you have to find how many days it will take till there are 6.25 grams of iodine left
every 8.1 days its mass is split in half
so start splitting it in half and every time you do, you add 8.1 days
50/2 =25 8.1
25/2 =12.5 + 8.1
12.5/2= 6.25 +8.1
now you have reached 1/8 of the original amount of Iodine-131
so to find how long it took just add 8.1+8.1+8.1
(this is the same as 8.1x3)
which equals 24.3
it will take 24.3 days for Iodine 131 to decay to 1/8 of its original mass.
(good luck on the regent if thats what your studying for :)
When multiplying numbers, the term with the least significant digits gives how many significant digits will be in the answer. 2.995 has the least with 4 "sig figs", so the answer will have 4 significant digits as well:
2.995/0.16685 = <span>17.9502547198
</span> ↑↑ ↑<span>↑
4 sig figs
So the answer is 17.95.</span>
Answer:
The composition of 1-propanol in vapor phase = 11.54 %
The composition of 2-propanol in vapor phase = 88.46 %
Explanation:
Mole fraction of components in liquid phase:
1-propanol = 
2-propanol = 
Partial pressure of 1-propanol =
Partial pressure of 2-propanol =
According to Raoults law:
Mole fraction of components in vapor phase:
1-propanol = 
The composition of 1-propanol in vapor phase:
100 × 0.1154= 11.54 %
2-propanol = 
The composition of 2-propanol in vapor phase:
100 × 0.8846 = 88.46 %
