Consider a triprotic acid like phosphoric acid or citric acid. which expression correctly describes the relative magnitudes of t
1 answer:
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Answer:
Explanation:
The balanced chemical equation :
To calculate the moles, we use the equation:
According to stoichiometry:
4 moles of produces = 902.0 kJ of energy
415.1 moles of produces =
of energy
Thus the change in enthalpy is
Explanation:
A mixture is defined as the substance that contains two or more different number of substances that are physically mixed together.
For example, a mixture of air which contains oxygen, nitrogen and other gases.
A mixture in which solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.
For example, sand in water is a heterogeneous mixture.
A homogeneous mixture is defined as the mixture in which solute particles are evenly distributed in a solvent.
A homogeneous mixture is a clear solution.
For example, salt dissolved in water is a homogeneous mixture.
A solution is defined as the substance in which two or more substances are mixed together.
A compound is defined as the substance that contains two or more different elements that chemically combined together in a fixed ratio by mass.
A element is defined as the substance that contains only one type of atoms.
For example, a piece of sodium element will contain only atoms of sodium.
Whereas a pure substance is defined as the substance which contains only one type of molecule or one type of atom.
For example, ,
etc are pure substances.
Thus, we can conclude that the terms which could be used to describe the given sample of air is as follows.
- pure chemical substance.
- heterogenous mixture.
- mixture.
Answer:
Energy= 2.7758 × 10^-11 J ;
71.112×10^-6 kJ.
Mass defect in Kilogram= 3.0885×10^-28 kg.
That is; 3.1×10^-28 kg(to two significant figure).
Explanation:
(Note: Check equation of reaction in the attached file/picture).
STEP ONE: we have to calculate the Mass defect.
Mass defect= Mass of reactants -- Mass of products.
Mass of the products: (140.9144+91.9262+3.060) u.
= 235.8666 u.
Mass of reactants: (1.0087+235.0439) u= 236.0526 u.
Therefore, the Mass defect= (236.0526 -- 235.8666) u
= 0.1860 u.
STEP TWO: Converting the Mass defect to energy;
0.18860 × 1.6605 × 10^27 kg
= 3.0885× 10^-28 kg
STEP THREE: Calculating energy released . Recall(from the question) c^2= 931.5 Mev/u. This is also equals to 9×10^16 m/s.
E=Mc^2.
Where E= energy released, c= speed of light, M= Mass.
Slotting in the values;
E= 3.0885×10^-28 kg × 9×10^16 m/s.
E=2.7758 × 10^-11 J.
Know that;( 1g of uranium × 1 mol of uranium ÷ 235.0439 g of uranium) × (6.002×10^23 atom of uranium/ 1 mol of uranium) × 2.7758× 10^-11.
=7.1112×10^-10 J
= 71.112×10^6 kJ.
