- Equilibrium shifts for slightly soluble compounds The reaction for the formation of a saturated solution of silver bromide (Ag
1 answer:
Answer:
1) Favor formation of reactant
2) Favor formation of product
3) Favor formation of product
4) Favor formation of product
5) Favor formation of product
Explanation:
The reaction is
The reaction is endothermic
1. Adding hydrobromic acid (HBr)
It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.
2. Lowering the concentration of bromide (Br-) ions
As we are decreasing the the concentration of product it will favor formation of more products
3. Heating the concentrations
If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.
4. Adding solid silver bromide (AgBr)
If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products
5. Removing silver (Ag+) ions
Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.
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<u>Answer:</u> The change in internal energy of the gas is 108.835 kJ
<u>Explanation:</u>
To calculate the work done for reversible expansion process, we use the equation:
where,
W = work done
P = pressure = 1.03 atm
= initial volume = 3.00 L
= final volume = 11.0 L
Putting values in above equation, we get:
(Conversion factor: 1 L. atm = 101.325 J)
Calculating the heat from power:
where,
Q = heat required
P = power = 150 W
t = time = 12 min = 720 s (Conversion factor: 1 min = 60 s)
Putting values in above equation:
The equation for first law of thermodynamics follows:
where,
Q = total amount of heat required = 108 kJ
dU = Change in internal energy = ?
W = work done = -0.835 kJ
Putting values in above equation, we get:
Hence, the change in internal energy of the gas is 108.835 kJ