Answer:
1. Removing them to an area of fresh air. This helps to prevents further poisoning by the carbon monoxide and increase the amount of oxygen entering into the body. This will help to reduce the concentration of carbon monoxide binding oxygen
2. Administering pure oxygen goes a long way to enhance ventilation and increase the oxygen saturation to 100%. This will help to overcome the effect of the carbon monoxide and promote more hemoglobin binding
Answer:
1. 0.90 are the initial moles of X and Y
2. 0.60 moles are the moles of Y and Z after the reaction
3. 0.90 moles of X and 0.30 moles of Y
4. 3X + 1Y → 2Z
Explanation:
1. For the reaction, initial moles of X and Y are:
500mL = 0.500L × (1.8 moles / L) = 0.90 are the initial moles of X and Y
2. After the reaction. The total volume is 500mL + 500mL = 1L
Moles Y and Z = 1L × (0.60 moles / 1L) = 0.60 moles are the moles of Y and Z after the reaction
3. As there is no moles of X after the reaction, all X reacts, that is 0.90 moles of X. And moles of Y that reacts are 0.90 mol - 0.60mol = 0.30 moles of Y
4. That means 3 moles of X reacts per mole of Y 0.90/0.30 = 3. Also, 2 moles of Z are produced per mole of Y 0.60/0.30 = 2.
That means balanced equation is:
aX + bY → cZ
<h3>3X + 1Y → 2Z</h3>
The second shell is left at 7, it should be filled to 8 to go to the next shell.
Given mass of tungsten, W = 415 g
Molar mass of tungsten, W = 183.85 g/mol
Calculating moles of tungsten from mass and molar mass:
