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Soloha48 [4]
2 years ago
7

Both Jacques Charles and Joseph Louis Guy-Lussac were avid balloonists. In his original flight in 1783, Jacques Charles used a b

alloon that contained approximately 31100 L of H2. He generated the H2 using the reaction between iron and hydrochloric acid: Fe(s)+2HCl(aq)→FeCl2(aq)+H2(g)
How many kilograms of iron were needed to produce this volume of H2 if the temperature was 21 ∘C? (For simplicity, assume that the pressure experienced by the balloon will be 1.00 atm.)
Chemistry
1 answer:
daser333 [38]2 years ago
3 0

Answer:

m_{Fe}=71.982 kg

Explanation:

First of all, we need  to calculate the moles of H2. Assuming the H2 is an ideal gas:

n=\frac{P*V}{T*R}

n=\frac{1atm*31100L}{294K*0.082 L*atm*mol^{-1}*K^{-1}}

n=1290 mol

Now, to produce 1 mol of H2 is required 1 mol of Fe:

m_{Fe}=n*M=1290mol*\{55.8 g}{mol}

m_{Fe}=71982 g=71.982 kg

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VMariaS [17]
M_{X} = \frac{(20.0\cdot 90\%)+(22.0\cdot10\%)}{100\%} = \frac{2020}{100} = 20.2[u]

answer: B
7 0
2 years ago
What is the index of hydrogen deficiency of a compound with a molecular formula of c6h15n?
7nadin3 [17]

Answer:

IHD = 0

Explanation:

Given that

C₆H₁₅N

Number of carbon atoms(n) = 6

Number of hydrogen atoms(x') = 15

Number of nitrogen atoms = 1

There is nitrogen atoms then x = x' -1

The index of hydrogen deficiency given as

IHD=\dfrac{2n+2-x}{2}

So

IHD=\dfrac{2n+2-x}{2}

IHD=\dfrac{2\time 6+2-(15-1)}{2}

IHD = 0

The index of hydrogen deficiency is zero.

6 0
2 years ago
What is the concentration of an alcl3 solution if 150. ml of the solution contains 550. mg of cl- ion?
valina [46]

The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M


calculation


concentration = moles /volume in liters


volume in liters = 150 /1000= 0.15 L


number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-


find the moles of Cl^- formed

moles =mass/molar mass

mass in grams= 550/ 1000 =0.55 grams

molar mass of Cl^- =35.5 g/mol


moles is therefore= 0.55/35.5 =0.0155 moles


by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles



concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M

6 0
2 years ago
Which of the following concerning second ionization energies is true?
Dennis_Churaev [7]

Answer:

D

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The fact is that the both elements belong to different groups in the periodic table. Mg is in group 12 while Al is in group 13. The outer most electron configuration for Mg2+=[Ne]3s0

Al+= [Ne]3s13p0

It is evident that in Al+, the second electron is to be removed from a filled 3s subshell which is energetically unfavourable. Unlike In Mg2+ where the two electrons are removed. There is always a tendency towards a quick loss of all the valence electrons in the valence shell. It will be more difficult to remove an electron from a filled shell.

5 0
2 years ago
A white powder, when heated, produces a colourless gas and a black solid. Is the white powder an element? I need reasons please
NeTakaya

Answer:It is not an element because elements are the purest form of a substance; hence, they are no longer broken down by heating

Explanation:

4 0
2 years ago
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