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dolphi86 [110]
2 years ago
5

Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). Match Term Definition Remo

ving ammonia A) No effect Removing hydrogen gas B) Shift to the right Adding a catalyst C) Shift to the left
Chemistry
1 answer:
pshichka [43]2 years ago
7 0

Answer:

The answers to the questions are given below.

Explanation:

According to Le Chatelier's principle, if an external constrain such as change in concentration, temperature or pressure is imposed on a chemical system in equilibrium, the equilibrium will shift in order to neutralize the effect.

A. Effective of removing ammonia, NH3.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Removing NH3 from the reaction simply means we are left with more reactants and no product. Therefore, the reactant will react to produce the product. Hence, the equilibrium position will shift to the right.

2. Effect of removing H2

N2(g) + 3H2(g) ⇌ 2NH3(g)

Remoing H2 simply means we have more products and less reactant. Therefore, the product will be convert to reactant. Hence, the equilibrium position will shift to the left.

C. Effect of adding a catalyst.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Catalyst does not affect the equilibrium position. It only creates an alternative path to arrive at the product within a short time. Hence, it has no effect.

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When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and
Vika [28.1K]
The correct answer is 1. Lose electrons and become positive ions.


I hope my answer was beneficial to you! c:
5 0
2 years ago
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A tank of oxygen has a volume of 40.0L and is held at a pressure of 159atm at 25∘C. What volume of O2 gas (in liters) would ther
Advocard [28]

Answer:

V2 = 6616 L

Explanation:

From the question;

Initial volume = 40L

Initial Pressure, P1 = 159atm

Initial Temperature T1 = 25 + 273 = 298K (Upon converting to Kelvin unit)

Final Volume, V2 = ?

Final Pressure, P2 = 1 atm

Final Temperature T2 = 37 + 273= 310K (Upon converting to Kelvin unit)

These quantities are related by the equation;

P1V1 / T1  = P2V2 / T2

V2 = T2 * P1 * V1 / T1 * P2

V2 = 310 * 159 * 40  /   (298 * 1)

V2 = 6616 L

6 0
1 year ago
A lead cylinder has a mass of 540 grams and a density of 2.70 g/ml. What is its volume
ch4aika [34]
Volume = Mass / Density

Volume = 540g / 2.70 g/ml

Volume = 200 ml 
3 0
2 years ago
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When 1.04g of cyclopropane was burnt in excess oxygen in a bomb calorimeter, the temperature rose by 3.69K. The total heat capac
STatiana [176]

Answer:

\Delta _{comb}H=-2,093\frac{kJ}{mol}

Explanation:

Hello!

In this case, since these calorimetry problems are characterized by the fact that the calorimeter absorbs the heat released by the combustion of the substance, we can write:

Q_{rxn}+Q_{cal}=0

Thus, given the temperature change and the total heat capacity, we obtain the following total heat of reaction:

Q_{rxn}=-14.01kJ/K*3.69K\\\\Q_{rxn}=-51.70kJ

Now, by dividing by the moles in 1.04 g of cyclopropane (42.09 g/mol) we obtain the enthalpy of combustion of this fuel:

n=\frac{1.04g}{42.09g/mol}=0.0247mol\\\\\Delta _{comb}H=\frac{Q_{rxn}}{n}\\\\  \Delta _{comb}H=-2,093\frac{kJ}{mol}

Best regards!

4 0
1 year ago
If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

6 0
2 years ago
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