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Lostsunrise [7]
2 years ago
12

The population of rabbits in a forest is decreasing. Foxes in that region are now competing with each other for the limited numb

er of rabbits in that forest. Which type of competition exists among these foxes?
Chemistry
2 answers:
sveta [45]2 years ago
6 0
Rabbits are eaten by predators such as foxes and wild dogs. If rabbit number decline predators ( foxes ) compete for the rest of the resources in forest. This is the competition between the members of same species or : interspecific competition. Foxes compete for the same resource ( rabbits ).
Answer: Interspecific competition.  
Bad White [126]2 years ago
4 0

The other answer is almost right; however, interspecific is when animals of contrasting species fight for a food source.


Intraspecific is when animals of the same species fight for a food source. Since the foxes are fighting each other, intraspecific is your answer.

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The pOH of a solution is 6.0. Which statement is correct? Use p O H equals negative logarithm StartBracket upper O upper H super
Katen [24]

Answer:

The pH of the solution is 8.

Explanation:

To which options are correct, let us determine the concentration of the hydroxide ion, [OH-] and the pH of the solution. This is illustrated below:

1. The concentration of the hydroxide ion, [OH-] can be obtained as follow:

pOH = –Log [OH-]

pOH = 6

6 = –Log [OH-]

–6 = Log [OH-]

[OH-] = Antilog (–6)

[OH-] = 1x10^–6 mol/L

2. The pH of the solution can be obtained as follow:

pH + pOH = 14

pOH = 6

pH + 6 = 14

pH = 14 – 6

pH = 8.

From the calculations made above,

[OH-] = 1x10^–6 mol/L

pH = 8.

Therefore, the correct answer is:

The pH of the solution is 8

3 0
2 years ago
What mass of solid lead would displace exactly 234.6 liters of water?
eimsori [14]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The mass of solid lead would displace exactly 234.6 liters of water should be <span>2,674,440</span>
6 0
2 years ago
Read 2 more answers
Formulating an Investigative Question In this experiment, you will use a track and a toy car to explore the concept of movement.
Solnce55 [7]

Answer:

A scientific question to be asked is; <em>What is the average speed of the toy car?</em>

Explanation:

A scientific question is a question which is well defined, the values in the question can be measured, and the inputs and outputs related to the question are controllable

The parameters measured in the experiment are;

The time elapsed during the movement of the car, <em>Δt</em>

The distance the car moves, <em>d</em>

From the obtained measurements, the value can be calculated is the average speed of the toy car as follows;

The \ average \ speed \ of \ the \ toy \ car, \ v_{avg} = \dfrac{d}{\Delta t}

Therefore, a scientific question to be asked that will be answered by doing the experiment is; What is the average speed of the toy car?

3 0
2 years ago
One mole of an ideal gas in a closed system, initially at 25°C and 10 bar, is first expanded adiabatically, then heated isochori
Igoryamba

Answer:

P_2=0.398bar=39800Pa

T_2=118.7K\\

Q=-3729.9J

W=-61753.24J

ΔU_T=0J

ΔH_T=0J

Explanation:

Hello,

At the first state, the molar volume is:

v_1=\frac{RT}{P_1} =\frac{8.314\frac{Pa*m^3}{molK}*298.15}{1x10^6Pa}=2.48x10^{-3}m^3

The volume in both the second and third state:

v_2=v_3=\frac{RT}{P_1} =\frac{8.314\frac{Pa*m^3}{molK}*298.15}{1x10^5Pa}=2.48x10^{-2}m^3

Now, as it is about an adiabatic process, one remembers the following relationships:

PV^\alpha =K\\TV^{\alpha-1}\\\alpha=\frac{Cp}{Cv}=\frac{7/2R}{5/2R}=1.4

- Next, for the aforesaid volumes and the first pressure, one computes the second pressure as:

P_2=\frac{P_1V_1^\alpha }{V_2^\alpha} =\frac{10bar*(2.48x10^{-3}m^3)^{1.4}}{(2.48x10^{-2}m^3)^{1.4}} =0.398bar=39800Pa

- And the temperature:

T_2=\frac{T_1V_1^{\alpha-1}}{V_2^{\alpha-1}} =\frac{298.15K*(2.48x10^{-3}m^3)^{1.4-1}}{(2.48x10^{-2}m^3)^{1.4-1}} =118.7K\\

- Q:

It is clear that the heat for the first process is 0 as it is adiabatic, but for the second one, it is computed as:

Q_2=nCv(T_2-T_1)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-3729.9J

Then the total heat:

Q=Q_1+Q_2=0-3729.9J=-3729.9J

- The work for the first process is:

W_1=\frac{P_2V_2-P_1V_1}{1-\alpha }=\frac{39800Pa*2.48x10^{-3}m^3-1x10^6Pa*2.48x10^{-2}m^3}{0.4} \\W_1=-61753.24J

It is clear that the second process is isochoric, so the work here is zero, thus, the total work is:

W=W_1+W_2=-61753.24J+0J=-61753.24J

- For the two processes, ΔU becomes the same value since the system returns to the initial temperature, so ΔU total is 0, thus, for each process, one's got:

U_1=nCv(T_2-T_1)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-3729.9J\\U_2=nCv(T_3-T_2)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(298.15K-118.7K)=3729.9J\\

- Finally, the total enthapy is also 0 due to same aforesaid reason, thus, each enthalpy is:

H_1=nCp(T_2-T_1)=1mol*\frac{7}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-5221.86J\\H_2=nCv(T_3-T_2)=1mol*\frac{7}{2}(8.314\frac{J}{mol*K})*(298.15K-118.7K)=5221.86J\\

Best regards.

8 0
2 years ago
1.000 mile is equal to 1609 meters. A truck is traveling at 42.00 km/h. What is the speed of the truck in miles per hour?
bija089 [108]

Around 24.85 miles per hour

, divide the length value by 1.60

3 0
2 years ago
Read 2 more answers
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