Answer : The value of is, 11.2
The value of is -9.04 kJ/mol
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -5.980 kJ/mol = -5980 J/mol
R = gas constant = 8.314 J/K.mol
T = temperature =
= equilibrium constant = ?
Now put all the given values in the above formula, we get:
Thus, the value of is, 11.2
Now we have to calculate the .
The formula used for is:
The given reaction is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant =
T = temperature =
Q = reaction quotient
[A] = concentration of A = 1.8 M
[B] = concentration of B = 0.55 M
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -9.04 kJ/mol
Explanation:
The given data is as follows.
Moles of propylene = 100 moles, = 300 K
= 800 K,
,
of propylene = 100 J/mol
Now, we assume the following assumptions:
Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.
W =
=
= 5 MJ
Thus, we can conclude that a minimum of 5 MJ work is required without any friction.
Here is the full question
Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 10 cm. The two liquids do not mix.
What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.
Express your answer in two significant figures and include the appropriate units (in cm)
Answer:
ΔH ≅ 3.73 cm
Explanation:
The pressure inside a liquid is known as hydrostatic pressure and which is represent by the formula:
P = ρ × g × h
where;
ρ is the density of the fluid
g is the gravitational constant
h is the height from the surface
From the question above;
For glycerine; we have:
density of glycerine = 1260 kg/m³
gravitational constant = 9.8 m/s²
height = ???
∴
----- equation (1)
On the other hand for alcohol:
density of alcohol is given as = 790 kg/m³
gravitational constant = 9.8 m/s²
height = 10 cm
∴
----------- equation (2)
if we equate equation 1 and 2 together; we have
Making the subject of the formula, we have :
= 6.269 cm
The difference in the height denoted by ΔH can therefore be calculated as:
ΔH
ΔH
ΔH = 3.731 cm
ΔH ≅ 3.73 cm (to two significant figures)