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Jobisdone [24]
2 years ago
9

95.8 l of fluorine gas is being held at a temperature of 24.5 c if the temperature were raised to 46.9c what would the new volum

e be
Chemistry
1 answer:
V125BC [204]2 years ago
6 0
V1/T1 = V2/T2
24.5 + 273 = 298.5K
46.9 + 273 = 319.9K

95.8/298 = V2/319.9
V2 = 102.66L
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Vanyuwa [196]

Answer:

The answer is A (number 1)

5 0
2 years ago
Jane made this picture to represent a chemical reaction: Two circles, one white and the other gray are shown on the left. A smal
7nadin3 [17]

It represents a decomposition reaction because one reactant breaks apart and forms two products.

Explanation:

The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.

In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.

                     XY   →   X + Y

  • Decomposition or cracking is the formation of two or more products from a single reactant.
  • The break down of a compound into individual atoms or molecules falls into this category.
  • The extreme instability of a compound drives such a reaction.
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      Find the image attached for more explanation:

Learn more:

Thermal decomposition brainly.com/question/11181911

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8 0
2 years ago
Read 2 more answers
HA and HB are two strong monobasic acids. 25.0cm3 of 6.0mol/dm3 HA is mixed with 45.0cm3 of 3.0mol/dm3 HB.
Lostsunrise [7]

Answer:

The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

(Option C)

Explanation:

Given;

concentration of HA, C_A = 6.0mol/dm³

volume of HA, V_A  = 25.0cm³, = 0.025dm³

Concentration of HB, C_B = 3.0mol/dm³

volume of HB, V_B = 45.0cm³ = 0.045dm³

To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;

C_iVi = C_fV_f

where;

C_i is initial concentration

V_i is initial volume

C_f is final concentration of the solution

V_f is final volume of the solution

C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3

Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

7 0
2 years ago
Element z reacts with bromine to form an ionic compound zbr2. A) state with reasons i) the physical properties of zbr2 at room t
kondor19780726 [428]

Answer:

The answer to your question is:

Explanation:

A) state with reasons

From the description we can conclude that the compound is a binary salt. Binary salts are form by a metal and a non metal, one of their characteristics is that the elements are attached by an ionic bond.

i) the physical properties of ZBr2 at room temperature

Crystals, high fusion and boiling points, they conduct water when dissolved in water, they are soluble in water but not in gasoline.

ii) whether z is a metal or non metal.

Z is a metal

3 0
2 years ago
How many molecules are in 3.6 grams of NaCl?
raketka [301]

Answer:

\boxed{\text{None}}

Explanation:

There are no molecules in NaCl, because it consists only of ions.

However, we can calculate the number of formula units (FU) of NaCl.

Step 1. Calculate the moles of NaCl

\text{No. of moles}=\text{3.6 g NaCl}\times \dfrac{\text{1 mol NaCl}}{\text{63.54 g NaCl}} = \text{0.0567 mol NaCl}

Step 2. Convert moles to formula units

\text{FU} = \text{0.0567 mol NaCl} \times \dfrac{6.022 \times 10^{23}\text{ FU NaCl}}{\text{1 mol NaCl}}\\\\= 3.4 \times 10^{22} \text{ FU NaCl}

There are \boxed{3.4 \times 10^{22} \text{ FU NaCl}} in 3.6 g of NaCl.

6 0
2 years ago
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