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2 years ago

How many grams of caf2 would be needed to produce 8.41×10-1 moles of f2?

1 answer:

5 0

Answer: 65.7 grams

Explanation:

1) ratio

Since 1 mole of CaF2 contains 1 mol of F2, the ratio is:

1 mol CaF2 : 1 mol F2

2) So, to produce 8.41 * 10^ -1` mol of F2 you need the same number of moles of CaF2.

3) use the formula:

mass in grams = molar mass * number of moles

molar mass of CaF2 = 40.1 g/mol + 2 * 19.0 g/mol = 78.1 g/mol

mass in grams = 78.1 g/mol * 8.41 * 10^ -1 mol = 65.7 grams

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A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is

Inessa05 [86]

Answer:

$T=2.78x10^3 \°C$

Explanation:

Hello,

In this case, considering that the safe temperature may be computed via the ideal gas law as we now the pressure, mass and volume via the dimensions:

$V=\pi r^2 h=\pi *(41.0cm)^2*49.2cm=2.60x10^5cm^3*\frac{1L}{1000cm^3} =260L$

The pressure in atm is:

$P=3.70MPa*\frac{1x10^6Pa}{1MPa} \frac{1atm}{101325Pa} =36.5atm$

And the moles considering the mass and molar mass (66 g/mol) of dinitrogen difluoride (N₂F₂):

$n_{N_2F_2}=2.50kg*\frac{1000g}{1kg}*\frac{1mol}{66g} =37.9mol$

In sich a way, by applying the ideal gas equation, which is not the best assumption but could work as an approximation due to the high temperature, the temperature, with three significant figures, will be:

$T=\frac{PV}{nR}=\frac{36.5Pa*260L}{37.9mol*0.082\frac{atm*L}{mol*K} }\\ \\T=3053.6K-273.15\\\\T=2.78x10^3 \°C$

Best regards.

7 0

1 year ago

If 0.640 g of beautiful blue crystals of azulene is dissolve in 99 g of benzen, the resulting solutions boils at 80.23 degrees c

devlian [24]

This problem handles boiling-point elevation, which means we will use the formula:

ΔT = Kb * m

Where ΔT is the difference of Temperature between boiling points of the solution and the pure solvent (Tsolution - Tsolvent). Kb is the ebullioscopic constant of the solvent (2.64 for benzene), and m is the molality of the solution.

Knowing that benzene's boiling point is 80.1°C, we solve for m:

Tsolution - Tsolvent = Kb * m

80.23 - 80.1 = 2.64 * m

m = 0.049 m

We use the definition of molality to calculate the moles of azulene:

0.049 m = Xmoles azulene / 0.099 kgBenzene

Xmoles azulene = 4.87 x10⁻³ moles azulene

We use the mass and the moles of azulene to calculate its molecular weight:

0.640 g / 4.875 x10⁻³ mol = 130.28 g/mol

A molecular formula that would fulfill that molecular weight is C₁₀H₁₀. So that's the result of solving this problem.

The actual molecular formula of azulene is C₁₀H₈.

6 0

2 years ago

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Arte-miy333 [17]

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1 year ago

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