Please Help Potassium sulfate has a solubility of 15g/100g water at 40 Celsius. A solution is prepared by adding 39.0g of potass
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Answer:
Given:
- Initial pressure:
.
- Volume was reduced from
to
.
- Temperature was raised from
to
.
New pressure: approximately (
.) (Assuming that the gas is an ideal gas.)
Explanation:
Both the volume and the temperature of this gas has changed. Consider the two changes in two separate steps:
- Reduce the volume of the gas from
.
- Raise the temperature of the gas from
.
By Boyle's Law, the pressure of an ideal gas is inversely proportional to the volume of this gas (assuming constant temperature and that no gas particles escaped or was added.)
For this gas, while
.
Let denote the pressure of this gas before the volume change (
.) Let
denote the pressure of this gas after the volume change (but before changing the temperature.) Apply Boyle's Law to find the ratio between
and
:
.
In other words, because the final volume is of the initial volume, the final pressure is
times the initial pressure. Therefore:
.
On the other hand, by Amonton's Law, the pressure of an ideal gas is directly proportional to the temperature (in degrees Kelvins) of this gas (assuming constant volume and that no gas particle escaped or was added.)
Convert the unit of the temperature of this gas to degrees Kelvins:
.
.
Let denote the pressure of this gas before this temperature change (
.) Let
denote the pressure of this gas after the temperature change. The volume of this gas is kept constant at
.
Apply Amonton's Law to find the ratio between and
:
.
Calculate , the final pressure of this gas:
.
In other words, the pressure of this gas after the volume and the temperature changes would be approximately .