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2 years ago

Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .

Chemistry

1 answer:

Nimfa-mama [501]2 years ago

7 0

Answer:

$\Delta H=-28.08 \frac{kJ}{mol}$

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

$\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}$

Which accounts for an exothermic chemical reaction.

Regards.

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2 years ago

Write a balanced equation for the reaction of nach3coo (also written as nac2h3o2) and hcl. express your answer as a chemical equ

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2 years ago

Read 2 more answers

A 5-ounce cup of raspberry yogurt contains 5.0 g of protein, 3.0 g of fat, and 13.3 g of carbohydrate. The fuel values for prote

castortr0y [4]

Answer:

as it has 17000 joules and 1 calorie has 4184 joules, this yogurt serving has 4.06 calories

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1 year ago

A 75 lb (34 kg) boy falls out of a tree from a height of 10 ft (3 m). i. What is the kinetic energy of the boy when he hits the

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Answer:

Kinetic energy of boy just before hitting the ground is $\approx$ 1000 J.

Speed of boy just before hitting the ground is 7.67 m/s

or 17.16 mi/hr.

Explanation:

Given that:

Mass of boy = 75lb = 34 kg

Height, h = 10ft = 3m

To find:

Kinetic energy of boy when he hits the ground.

As per law of conservation of energy The potential energy gets converted to kinetic energy.

$\therefore$ Kinetic energy at the time boy hits the ground = Initial potential energy of the boy when he was at the Height 'h'

The formula for potential energy is given as:

$PE = mgh$

Where m is the mass

g is the acceleration due to gravity, g = 9.8 $m/s^2$

h is the height of object

Putting all the values:

PE = $34 \times 9.8 \times 3 \approx 1000\ J$

Hence, Kinetic energy is $\approx$ 1000 J.

Formula for Kinetic energy is:

$KE = \dfrac{1}{2}mv^2$

where m is the mass and

v is the speed

Putting the values and finding v:

$1000 = \dfrac{1}{2}\times 34 \times v^2\\\Rightarrow v^2 = 58.82\\\Rightarrow v = 7.67\ m/s$

Given that:

1 m = 1.094 yd and 1 mi = 1760 yd

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2 years ago

A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed fro

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Answer:

The correct answer is option C.

Explanation:

1.0 g sample of a cashew :

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3.0 g sample of a marshmallows :

Heat released on combustion of 3.0 g sample of a marshmallows = -Q'

We have mass of water = m = 2000 g

Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water : Q'

$Q'=2000 g\times 4.184 J/g^oC\times 5^oC=41,840 J$

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Heat released on 1.0 g sample of a marshmallows : q

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Heat released on combustion of 1.0 gram of marshmallows -13,946.67 J.

-20,920 J. > -13,946.67 J

The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.

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2 years ago