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choli [55]
2 years ago
7

What atomic or hybrid orbitals make up the bond between c2 and o in acetaldehyde, ch3cho?

Chemistry
2 answers:
SSSSS [86.1K]2 years ago
8 0

Acetaldehyde is an organic compound (a compound containing C atoms) composed of a carbonyl group. On the other hand, a carbonyl group is a functional group containing C = O. The hybrid orbitals of a compound determines the number pi and s orbitals in the electronic configuration. For a single bond, there are two s orbitals. For double bonds, on the other hand, the number of s orbital bond is 1 while the number of pi bonds is 2. For triple bonds, there are three pi bonds present in the cloud.

Thus for a c = O bond, the atomic orbital configuration is sp3 containing 1 s orbital and 2 pi bonds. 

Margaret [11]2 years ago
7 0

Answer:

In terms of central atom carbon:

three sp2 hybridized orbitals

one "2p" orbital.

one sp2 hybridized orbital and one "2p" orbital bonds with oxygen atom.

Explanation:

In acetaldehyde we have two carbons.

One carbon is simple alkyl carbon

The other carbon is carbonyl carbon

The carbonyl carbon is bonded to the alkyl carbon and hydrogen by sigma bonds (one with each) and to the oxygen atom by one sigma and one pi bond.Which means that there are three sigma bonds and one pi bond.

The hybridisation of carbonyl carbon is sp2.

The atomic orbitals involved are:

three "2p" orbitals

one "2s" orbital

Out of the three "2p" orbitals : two are involved in hybridization.

The third one is showing side ways overlapping with the "2p" orbital of oxygen atom.

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Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?
cluponka [151]

Answer:

3.1°C

Explanation:

Using freezing point depression expression:

ΔT = Kf×m×i

<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>

Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:

9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m

Replacing in freezing point depression formula:

ΔT = 5.12°cm⁻¹×0.472m×1

ΔT = 2.4°C

As freezing point of benzene is 5.5°C, the new freezing point of the solution is:

5.5°C - 2.4°C =

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3 0
2 years ago
Washing soda is a hydrate of sodium carbonate. Elemental analysis of a sample of washing soda gave 4.20% C and 7.05% H. What is
kozerog [31]

Answer:

Na₂CO₃ · 10H₂O

Explanation:

The formula for sodium carbonate hydrate is:

Na₂CO₃ · xH₂O

The unknown "x" is the number of water molecules contained in the hydrate.

To find "x" we have to use the hydrogen percentage in the sample, 7.05 % H.

First we calculate the molecular weight of Na₂CO₃ · xH₂O:

molecular weight of Na₂CO₃ · xH₂O = 23 × 2 + 12 + 16 × 3 + 18x

molecular weight of Na₂CO₃ · xH₂O = 106 + 18x  g/mole

Now we devise the fallowing reasoning tanking in account 1 mole of Na₂CO₃ · xH₂O:

if in        106 + 18x grams of Na₂CO₃ · xH₂O we have 2x grams of hydrogen

then in  100 grams of Na₂CO₃ · xH₂O we have 7.05 grams of hydrogen

106 + 18x = (100 × 2x) / 7.05

106 + 18x = 28.4x

106 = 28.4x - 18x

106 = 10.4x

x = 106 / 10.4

x = 10.2 ≈ 10

The formula for the washing soda is Na₂CO₃ · 10H₂O.

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2 years ago
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Answer:

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