Convert 2.17 x 10 -8 Mg into pg

Chemistry

1 answer:

viktelen [127]2 years ago

4 0

This answer is 24 because 2.17 x 10 -8 is 24 so that would be your answer

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In an experiment a student mixes a 50.0 mL sample of 0.100 M AgNO₃(aq) with a 50.0 mL sample of 0.100 M NaCl(aq) at 20.0°C in a

drek231 [11]

The enthalpy change of the precipitation reaction is 84 kJ/mole

Why?

The chemical equation for the reaction is

AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)

To find the enthalpy change we need to apply the following equation

$\Delta H =\frac{Q}{n}$

To find the heat (Q):

$Q=m*C*\Delta T=(100g)*(4.2 J/g*^\circ C)*(21^\circ C-20^\circ C)\\\\Q=420J$

Now, to find the number of moles that react (n):

$n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles$

Having these two values we can plug in the first equation:

$\Delta H= \frac{420J}{0.005moles}=84000J/mole=84kJ/mole$

Have a nice day!

5 0

2 years ago

Jolene wants to experiment with sugar cubes. Which of the following causes a sugar cube to only change physically, not chemicall

Ugo [173]

If you cut the cube and keep all the pieces you are causing only physical change

5 0

2 years ago

During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/mi

Eduardwww [97]

The solution for this problem would be:
The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min
So solving for the rate will be mass over t = m/t = 227/0.25 = 908 g/min would be the answer for this problem.

3 0

2 years ago

Given the following reactions Fe2O3 (s) + 3CO (s) → 2Fe (s) + 3CO2 (g) ΔH = -28.0 kJ 3Fe (s) + 4CO2(s) → 4CO (g) + Fe3O4(s) ΔH =

Taya2010 [7]

Answer: The enthalpy of the reaction is -109 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$Fe_2O_3(s)+3CO(s)\rightarrow 2Fe(s)+3CO_2(g)$ $\Delta H=-28.0kJ$ $\times 3$