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Archy [21]
2 years ago
6

If you produce 14.5 g of O2 in the lab from a reaction that you showed by calculation could produce a maximum of 22.0 g of O2, w

hat is your percent yield?
Chemistry
2 answers:
Komok [63]2 years ago
5 0

Percent yield is simply the ratio of the actual amount produced over the theoretical amount that can be produced. In this case that would be:

percent yield = actual amount / theoretical amount

percent yield = (14.5 g / 22.0 g) * 100%

<span>percent yield = 65.91%</span>

almond37 [142]2 years ago
5 0

Answer: 65.9 %

Explanation:

The formula for calculating percentage yield is:

Percentage yield = \frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Given : Experimental yield = 14.5 g

Theoretical yield = 22.0 g

Putting in the values we get:

Percentage yield = \frac{14.5}{22.0}\times 100=65.9\%

Therefore, the percentage yield is 65.9 %.

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In the heat equation, what does Q represent? heat required to raise the temperature specific heat of the substance mass of the s
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Draw the Lewis structure (including resonance structures) for diazomethane (CH2N2)(CH2N2). For each resonance structure, assign
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Answer : The Lewis-dot structure and resonating structure of CH_2N_2 is shown below.

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

Resonance structure is defined as any of two or more possible structures of the compound. These structures have the identical geometry but have different arrangements of the paired electrons. Thus, we can say that the resonating structure are just the way of representing the same molecule.

First we have to determine the Lewis-dot structure of CH_2N_2.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CH_2N_2

As we know that carbon has '4' valence electrons, nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in CH_2N_2 = 4 + 2(1) + 2(5) = 16

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For structure 1 :

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on H}=1-0-\frac{2}{2}=0

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\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on H}=1-0-\frac{2}{2}=0

\text{Formal charge on C}=4-0-\frac{8}{2}=0

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