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miskamm [114]
2 years ago
12

Consider isotopes ions protons and electrons. how many of these did dalton not discuss in his atomic theory?

Chemistry
1 answer:
MAVERICK [17]2 years ago
8 0

Answer: He did not discuss about any of these.

Explanation: Dalton proposed some of the postulates for his atomic theory. They are:

1) Matter is made up of atoms which are not divisible.

2) Atoms of different elements combine in a fixed ratio to form compounds.

3) The atomic properties of given element are same including mass. This states that all the atoms of an element have same mass but the atoms of different elements have different masses.

4) No atoms are either created or destroyed during a chemical reaction.

5) Atoms of an element are identical in mass, size and other chemical and physical properties.

As it is visible from the postulates, he only discussed only about the atoms but not subatomic particles or isotopes.

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How many liters of a 0.0550 M NaF solution contain 0.163 moles of NaF?
Kobotan [32]

Answer : The volume of solution will be 2.96 liters.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

In this question, the solute is NaF.

Now put all the given values in this formula, we get:

0.0550M=\frac{0.163mole}{\text{Volume of solution (in L)}}

\text{Volume of solution (in L)}=\frac{0.163mole}{0.0550M}

\text{Volume of solution (in L)}=2.96L

Therefore, the volume of solution will be 2.96 liters.

3 0
1 year ago
Neutrons were discovered in 1932, more than 10 years after the existence of isotopes was confirmed. What property of electrons a
kirza4 [7]

Protons and neutrons are the sub-atomic particles present in the nucleus of an atom where as electrons are present revolving round the nucleus in orbits. Electrons are negatively charged, protons are positively charged where as a neutron is a neutral species. It is the presence of electric charge that lead to the discovery of electrons (negative charge) and protons (positive charge), while it took time to discover neutral as they were electrically neutral species. Neutrons carrying no charge were not detected easily by passing electromagnetic radiations. Therefore, neutrons were the last of the three subatomic particles, to be discovered.

8 0
1 year ago
Which phrase best describes a chemical reaction? A. mixing two substances B. the combustion of a substance C. forming or breakin
nirvana33 [79]
The answer for the problem is C
6 0
2 years ago
Read 2 more answers
6. From the values of ΔH and ΔS, predict which of the following reactions would be spontaneous at 25ºC: Reaction A: ΔH = 10.5 kJ
qwelly [4]

Answer:

Both reaction A and reaction B are non spontaneous.

Explanation:

For a spontaneous reaction, change in gibbs free energy (\Delta G) should be negative.

We know, \Delta G=\Delta H-T\Delta S, where T is temperature in Kelvin scale.

Reaction A: \Delta G=(10.5\times 10^{3})-(298\times 30)J/mol=1560J/mol

As \Delta G is positive therefore the reaction is non-spontaneous.

If at a temperature T K , the reaction is spontaneous then-

\Delta H-T\Delta S< 0

or, T> \frac{\Delta H}{\Delta S}

or, T> \frac{10.5\times 10^{3}}{30}

or, T> 350

So at a temperature greater than 350 K, the reaction is spontaneous.

Reaction B: \Delta G=(1.8\times 10^{3})-(-113\times 298)J/mol=35474J/mol

As \Delta G is positive therefore the reaction is non-spontaneous.

If at a temperature T K , the reaction is spontaneous then-

\Delta H-T\Delta S< 0

or, T> \frac{\Delta H}{\Delta S}

or, T> \frac{1.8\times 10^{3}}{-113}

or, T> -16

So at a temperature greater than -16 K, the reaction is spontaneous.

3 0
2 years ago
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol×\frac{1mol}{80,043g}X

Y = 321J/g X <em>(2)</em>

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0
2 years ago
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