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Bumek [7]
2 years ago
8

A chemist adds 180.0 mL of a 1.42M sodium carbonate (Na CO,) solution to a reaction flask. Calculate the millimoles of sodium ca

rbonate the chemist has added to the flask. Round your answer to 3 significant digits. mmol
Chemistry
1 answer:
svet-max [94.6K]2 years ago
6 0

Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256

Explanation:

Molarity is defined as the number of moles dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{milli moles of solute}}{\text{Volume of solution in ml}}     .....(1)

Molarity of BaCl_2 solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in equation 1, we get:

1.42M=\frac{\text{milli moles of }BaCl_2}{180.0ml}\\\\\text{milli moles of }BaCl_2}={1.42M\times 180.0ml}=256milli mol

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.

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Answer: Storks are found in medium to tall trees that occur in stands located either in swamps or on islands ... also an important feeding habitat for the nesting birds. ... six percent in dead oaks

Explanation: There important because Storks only live in these types of trees

Vote me for brainliest!!!!

8 0
1 year ago
"which of these nitrogen compounds is in the most reduced state?"
gtnhenbr [62]
Because I can't see your options, all I can say is to look for the one whose numbers can't be simplified any further
8 0
2 years ago
ANSWER Soon!!
vichka [17]

Answer:

  • 1. 0.1683 mol
  • 2. 1.191 g
  • 3. 0.02695 mol
  • 4. Na₂Cl₃
  • 5. The empirical formula obtained is not correct. This is likely due to experimental errors, since much precision was required (the masses are determined in thousandths of grams).

Explanation:

<em><u></u></em>

<em><u>1. How many moles of elemental sodium were used in the reaction?</u></em>

Since all of the solid sodium is used up by the reaction, you can cancluate the number of moles of elemental sodium used dividing the mass by the molar mass:

  • number of moles = mass in grams / atomic mass

  • mass in grams = 0.3870 g (given)

  • atomic mass = 22.990 g/mol

  • number of moles = 0.3870 g / 22.990 g/mol = 0.1683 mol

<u><em>2. What is the mass of chlorine gas used in the reaction?</em></u>

a) Mass of chlorine gas introduced in the flask = mass of the stoppered flask after filling it with chlorine gas - mass of the empty flask with the sopper

  • Mass of chlorine gas introduced = 158.1743g - 156.1870g = 1.9873 g

b) Mass of chlorine gas unreacted = 0.7962 g (given)

c) Mass of chlorine gas used = mass of chorine gas introduced in the flask - mass of chlorine gass un reacted

  • Mass of chlorine gas used = 1.9873g - 0.7962g = 1.1911g

<u><em>3. How many moles of chlorine were used in the reaction?</em></u>

  • molar mass of chlorine gas, Cl₂ = 2 × 35.453 g/mol = 70.906 g/mol

  • number of moles = mass in grams / molar mass = 1.911g / 70.906g/mol = 0.02695 mol

<u><em>4. What is the empirical formula of sodium chloride based on the experimental data?</em></u>

Divide the number of moles of each element by the smalles number of moles:

  • Na: 0.01683 / 0.01683 = 1
  • Cl = 0.02695 / 0.01683 = 1.6

Multiply by 2 to obtain whole numbers:

  • Na = 2
  • Cl = 3.2 = 3

  • Empirical formula Na₂Cl₃

<u><em></em></u>

<u><em>5. Was the empirical formula you obtained correct using the chemists data correct? Why? </em></u>

<u><em></em></u>

No, the empirical formula you obtained using the chemists data is not correct, because the correct empirical formula of sodium chloride is NaCl.

That is, there is 1 atom of sodium per every atom of chlorine in one chemical formula of NaCl, but that is not reflected by the empirical formula Na₂Cl₃.

That is a demostration of big experimental errors. You can speculate that the errors are likely due to problems of procedure collecting the gas or errors in measuring the masses.

As you see, the masses are measured to thousandths of grams, which requires much precision; thus smalls absolute errors could produce huge relative errors.

7 0
2 years ago
When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala
Orlov [11]

Answer:

q = -176kJ

Explanation:

HCl and NH3 reacts as following to NH4Cl

HCl(g) + NH3(g)=========>NH4Cl(s)   : ΔH = -176 KJ

Clearly,

ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .

therefore, the value of heat evolved as q = -176kJ

8 0
1 year ago
Devon’s laboratory is out of material to make phosphate buffer. He is considering using sulfate to make a buffer instead. The pk
sesenic [268]

Answer:

Is not possible to make a buffer near of 7.

Optimal pH for sulfate‑based buffers is 2.

Explanation:

The dissociations of H₂SO₄ are:

H₂SO₄ ⇄ H⁺ + HSO₄⁻ pka₁ = -10

HSO₄⁻ ⇄ H⁺ + SO₄²⁻ pka₂ = 2.

The buffering capacity is pka±1. That means that for H₂SO₄ the buffering capacity is in pH's between <em>-11 and -9 and between 1 and 3</em>, having in mind that pH's<0 are not useful. For that reason, <em>is not possible to make a buffer near of 7.</em>

The optimal pH for sulfate‑based buffers is when pka=pH, that means that optimal pH is <em>2.</em>

<em />

I hope it helps!

4 0
2 years ago
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