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serious [3.7K]
2 years ago
11

Salts and acids are examples of inorganic compounds called _____, which dissociate in water to release ions.

Chemistry
2 answers:
g100num [7]2 years ago
8 0

Salts and acids are examples of inorganic compounds called Electrolytes which dissociate in water to release ions.

<h2>Further Explanation: </h2><h3>A compound  </h3>
  • A compound is a substances that contains two or more different atoms that are bonded together.
  • When the atoms are similar the substance is known as a molecule, therefore not all molecules are compounds.
<h3>Electrolytes</h3>
  • Electrolytes are substances that are either in molten or aqueous form that discharged by passing electric current through them. They dissociate into ions while in molten or solution form.
  • These compounds are made of mobile ions which are responsible for the conduction of electricity.
  • Examples includes, soluble salts, ionic compounds, acids, and bases etc.
<h3>Salt </h3>
  • A salt is a substance that is formed when an acid reacts with a base or when the hydrogen part of acid is replaced by metal ion or an ammonium ion.
<h3>Ionic compounds </h3>
  • Ionic compounds are compounds that contain ions. They are as a result of ionic bonding between a metal atom and a non-metal atom.
  • During ionic bonding formation the metallic atom looses electrons while the non-metallic atom gains electrons.
  • Ionic compounds contains both negatively charged ion(anion) and positively charged ion (cation).
  • Examples of ionic compounds, NaCl, LiF, KCl, Cs2S, KBr, PbS etc.
  • Most ionic compounds may act as electrolytes.

Keywords: Compound, electrolytes, salts, ionic compounds, soluble acids, bases.

<h3>Learn more about: </h3>
  • Compound: brainly.com/question/10052458
  • Electrolytes: brainly.com/question/4053091
  • Electrolysis: brainly.com/question/11868966
  • Ionic compounds: brainly.com/question/10052458

Level: High school

Subject: Chemistry

Topic: Electrolysis

Sub-topic: Electrolytes.

Blizzard [7]2 years ago
4 0

Answer:

Salts and acids are examples of inorganic compounds called <u><em>electrolytes</em></u>.

Explanation:

Electrolytes are the substances which dissociates into ions when dissolved in water and due to this they are able to conduct electric current through them.  These compounds in solid form does not conduct electricity due to the absence of free ions.

For example: Sodium chloride , sulfuric acid etc.

NaCl(aq)\righarrow = Na^+(aq)+Cl^-(aq)

H_2SO_4(aq)\rightarrow SO_4^{2-}(aq)+2H^+(aq)

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When 50 ml (50 g) of 1.00 m hcl at 22oc is added to 50 ml (50 g) of 1.00 m naoh at 22oc in a coffee cup calorimeter, the tempera
vitfil [10]

Answer:

\boxed{\text{2700 J}}

Explanation:

HCl + NaOH ⟶ NaCl + H₂O

There are two energy flows in this reaction.  

Heat of reaction + heat to warm water = 0  

           q₁             +              q₂                 = 0  

           q₁             +          mCΔT              = 0  

Data:

    m(HCl) = 50 g

m(NaOH) = 50 g

           T₁ = 22       °C

          T₂ = 28.87 °C

           C = 4.18 J·°C⁻¹g⁻¹

Calculations:

 m = 50 + 50 = 100 g

ΔT = 28.87 – 22 = 6.9 °C

 q₂ = 100 × 4.18 × 6.9 = 2900 J

q₁ + 2900 = 0

q₁ = -2900 J

The negative sign tells us that the reaction produced heat.

The reaction produced \boxed{\textbf{2900 J}}.

7 0
2 years ago
A 32.5 g piece of aluminum (which has a specific heat capacity of 0.921 J/g°C) is heated to 82.4°C and dropped into a calorimete
N76 [4]

Answer:

The mass of water = 219.1 grams

Explanation:

Step 1: Data given

Mass of aluminium = 32.5 grams

specific heat capacity aluminium = 0.921 J/g°C

Temperature = 82.4 °C

Temperature of water = 22.3 °C

The final temperature = 24.2 °C

Step 2: Calculate the mass of water

Heat lost = heat gained

Qlost = -Qgained

Qaluminium = -Qwater

Q = m*c*ΔT

m(aluminium)*c(aluminium)*ΔT(aluminium) = -m(water)*c(water)*ΔT(water)

⇒with m(aluminium) = the mass of aluminium = 32.5 grams

⇒with c(aluminium) = the specific heat of aluminium = 0.921 J/g°C

⇒with ΔT(aluminium) = the change of temperature of aluminium = 24.2 °C - 82.4 °C =  -58.2 °C

⇒with m(water) = the mass of water = TO BE DETERMINED

⇒with c(water) = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = 24.2 °C - 22.3 °C = 1.9 °C

32.5 * 0.921 * -58.2 = -m * 4.184 * 1.9

-1742.1 = -7.95m

m = 219.1 grams

The mass of water = 219.1 grams

8 0
2 years ago
If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lu
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Answer:

1.505×10^23 atoms of lead

Explanation:

Volume of lead in the lungs = total volume of lungs = 5.60L

1 mole = 22.4L

5.6L of lead = 5.6/22.4 = 0.25 mole

From Avogadro's law

1 mole of lead contains 6.02×10^23 atoms of lead

0.25 mole of lead = 0.25×6.02×10^23 = 1.505×10^23 atoms of lead

6 0
2 years ago
State whether each of the following will be more soluble in water or hexane i. Butane ii. Ch3cooh iii. K2so4
ioda

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Hence , from the question ,

Water is a polar molecule , and hence it will dissolve only the polar molecule , i.e. , from the given options the polar molecule is , iii. K₂SO₄

Hexane , is a non - polar molecules ,  hence it will dissolve only the non polar molecule , i.e. , from the given options the non polar molecule is i. Butane .

3 0
2 years ago
For the reaction c + 2h2 → ch4, how many moles of hydrogen are required to produce 10 moles of methane, ch4?
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                                                 C+2H2 -------> CH4   
from reaction                              2 mol           1 mol
from the problem                       x mol           10 mol

x=2*10/1 = 20 mol

Answer: 20 mol of H2.

4 0
2 years ago
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