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polet [3.4K]
2 years ago
12

Write an equation that shows the formation of the phosphide ion from a neutral phosphorus atom.

Chemistry
2 answers:
atroni [7]2 years ago
8 0

Answer: P+3e^-\rightarrow P^{3-}

Explanation: Phosphorous atom is the element with atomic number 15 and thus contains 15 electrons.

P:15:1s^22s^22p^63s^23p^3

Thus it is short of 3 electrons to attain stable noble gas configuration. Thus it gains three electrons and converts to phosphide ion (P^{3-}) with 18 electrons.

P^{3-}:18:1s^22s^22p^63s^23p^6

Vlad1618 [11]2 years ago
5 0

From reference or science books, we can actually know that the elementary charge of phosphorus is -3. Since it is negative, this means that it has an excess of electrons, which further means that it takes up 3 electrons to become an ion. Therefore the equation can be written as:

<span>P  +  3e  --->  P3- </span>

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mastering chem If the experiment below is run for 60 s, 0.16 mol A remain. Which of the following statements is or are true? At
Dvinal [7]

Answer: All of the statements are true.

Explanation:

(a) Considering the system mentioned in the equation:-

The sum of total moles in the flask will always be equal to 1 which leads to confirmation of this statement as for 60 secs= 0.16 mol A and 0.84 mol B

(b) 0<t< 20s,  mole A got reduced from 1 mole to 0.54 moles while at 40s to 60s A got decreased from 0.30 moles to 0.16 moles.

0 to 20s is 0.46 (1 - 0.54 = 0.46)mol whereas,

40 to 60s is 0.14 (0.30-.16 = 0.14) mol

(0.46 > 0.14) mol leading this statement to be true as well.

(c) Average rate from t1 = 40 to t2 = 60 s is given by:

\delta moles/\delta time  = 0.30-0.16/60-40 = 0.007 Mol/s which is true as well

7 0
2 years ago
Find the mass in grams of 1.40x10^23 molecules of n2
mina [271]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

</span>1.40x10^23 molecules of N2 ( 1 mol / 6.022 x 10^23 molecules ) ( 28.02 g / mol ) = 6.51 g N2
7 0
2 years ago
40pionts
Pachacha [2.7K]

Problem One (left)

This is just a straight mc deltaT question

<em><u>Givens</u></em>

m = 535 grams

c = 0.486 J/gm

tf = 50

ti = 1230

Formula

E = m * c * (ti - tf)

Solution

E = 535 * 0.486 * ( 1230 - 50)

E = 535 * 0.486 * (1180)

E = 301077

Answer: A

Problem Two

This one just requires that you multiply the two numbers together and cut it down to 3 sig digits.

E = H m

H = 2257 J/gram

m = 11.2 grams

E = 2257 * 11.2

E = 25278  to three digits is 25300 Joules. Anyway it is the last one.

Three

D and E are both incorrect for the same reason. The sun and stars don't contain an awful lot of Uranium (1 part of a trillion hydrogen atoms). It's too rare. The other answers can all be eliminated because U 235 is pretty stable in its natural state. It has a high activation complex.

Your best chance would be enriched Uranium (which is another way of saying refined uranium). That would be the right environment. Atomic weapons and nuclear power plants (most) used enriched Uranium. You can google "Little Boy" if you want to know more.

Answer: B

Four

The best way to think about this question is just to get the answer. Answer C.

A: incorrect. Anything sticking together implies a larger and larger result. Gases don't work that way. They move about randomly.

B: Wrong. Heat and Temperature especially depend on movement. Stopping is not permitted. If a substance's molecules stopped, the substance would experience an extremely uncomfortable temperature drop.

C: is correct because the molecules neither stop nor do they stick. The hit and move on.

D: Wrong. An ax splitting something? That is not what happens normally and not with ordinary gases. It takes more energy that mere collisions or normal temperatures would provide to get a gas to split apart.

E: Wrong. Same sort of comment as D. Splitting is not the way these things work. They bounce away as in C.

Five

Half life number 1 would leave 0.5 grams behind.

Half life number 2 would leave 1/2 of 1/2 or 1/4 of the number of grams left.

Answer: 0.25

Answer C

6 0
2 years ago
If 29.4 mL of ethanol is dissolved in water to make 359 mL of solution, what is the concentration expressed in volume/volume % o
Sveta_85 [38]

Answer: 8.2\%

Explanation:- Volume percentage is the ratio of volume of solute to the volume of solution defined in terms of percentage.

{\text {volume percentage}}=\frac{\text {volume of solute}}{\text {volume of solution}}\times 100\%

Given: volume of solute = 29.4 ml

Volume of solution= 359 ml

{\text {volume percentage}=\frac{29.4}{359}\times 100\%=8.2\%


6 0
2 years ago
For each case below, identify the most likely value for x: a. BHx b. CHx c. NHx d. CH2Clx
Snezhnost [94]

Answer:

BHx, x=3

CHx, x=4

NHx, x=3

CH2Clx, x=2

Explanation:

We have to know that the value of x must depend on the valency of the central atom. If we look at each of the species;

Boron has a common valency of 3

Carbon has a common valency of 4

Nitrogen has a common valency of 3

The valency of each elements will determine the most likely value of x as outlined in the answer above.

8 0
2 years ago
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