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polet [3.4K]
1 year ago
12

Write an equation that shows the formation of the phosphide ion from a neutral phosphorus atom.

Chemistry
2 answers:
atroni [7]1 year ago
8 0

Answer: P+3e^-\rightarrow P^{3-}

Explanation: Phosphorous atom is the element with atomic number 15 and thus contains 15 electrons.

P:15:1s^22s^22p^63s^23p^3

Thus it is short of 3 electrons to attain stable noble gas configuration. Thus it gains three electrons and converts to phosphide ion (P^{3-}) with 18 electrons.

P^{3-}:18:1s^22s^22p^63s^23p^6

Vlad1618 [11]1 year ago
5 0

From reference or science books, we can actually know that the elementary charge of phosphorus is -3. Since it is negative, this means that it has an excess of electrons, which further means that it takes up 3 electrons to become an ion. Therefore the equation can be written as:

<span>P  +  3e  --->  P3- </span>

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Which of the following classification of matter includes material that can no longer be identified by their individual propertie
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1.What is the name of the compound CuCO3?. a. Copper (I) Carbonate. b. Copper (II) Carbonate. c. Copper Carbon Oxide . d. Copper
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1. Answer;

Copper (ii) carbonate.

The name of the compound CuCO3 is copper (ii) carbonate.

Explanation;

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2. Answer;

Yes

Ca2+ reacted with Na2S to form CaS and Na+

Explanation:

Calcium ions reacts with sodium sulfide to form calcium sulfide and sodium ions.

For example; a salt of calcium, calcium carbonate reacts with sodium sulfide to form sodium carbonate and calcium sulfide.

3. Answer;

NaCl and Ag+ do not form a product

Explanation;

The reaction between sodium chloride and silver metal will not take place. This is because silver (Ag) is less reactive than sodium metal and therefore cannot displace sodium from its salt. In other words, silver metal is lower in the reactivity series as compared to sodium metal which indicates sodium metal is more reactive than silver.

4. Answer;

Formation of a white precipitate ; this indicates that silver sulfide is insoluble in water.

Explanation;

When an aqueous solution containing Ag+ ions is added to aqueous solution of sodium sulfide (Na2S), there will be formation of white precipitate. Formation of white precipitate indicates that a reaction has taken place to form a water insoluble compound. The water insoluble compound occurs as a precipitate. The white precipitate is silver sulfide (Ag2S)

2 Ag+ (aq) + Na2S(aq) ----- Ag2S (s) + 2 Na+ (aq)

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1 year ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
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Answer:

pH → 7.46

Explanation:

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We do not consider [H₂O] in the expression for the constant.

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0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

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- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

5 0
2 years ago
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